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zmey [24]
3 years ago
9

Plz help w/ Geometry!!! Will give Brainliest!!!

Mathematics
1 answer:
e-lub [12.9K]3 years ago
7 0

Answer:

\large\boxed{b.\ 1cm\xrightarrow{\ \ \ \ \ \ \ \ }8\ mi}

Step-by-step explanation:

6.5\ cm\xrightarrow{\ \ \ \ \ \ \ \ }52\ mi\qquad\text{divide both sides by}\ 6.5\\\\\dfrac{6.5}{6.5}\ cm\xrightarrow{\ \ \ \ \ \ \ \ }\dfrac{52}{6.5}\ mi\\\\1cm\xrightarrow{\ \ \ \ \ \ \ \ }8\ mi

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8 0
3 years ago
What's the answer to this math problem?<br><br><br> 3c+2= −10
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8 0
3 years ago
the second term of a geometric sequence is 18 and the fourth term is 8 find the common ratio . And find the sum of the first 6 t
777dan777 [17]

Answer:

  • ratio: 2/3
  • sum: 73 8/9

Step-by-step explanation:

The general term of a geometric sequence is ...

  an = a1·r^(n-1)

You have the 2nd and 4th terms, so ...

  a2 = a1·r^(2-1) = a1·r

  a4 = a1·r^(4-1) = a1·r^3

We can find r from the ratio ...

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Then r is ...

  r = √(4/9) = 2/3 . . . . the common ratio

The first term is ...

  a2 = 18 = a1·(2/3)

  a1 = (3/2)·18 = 27

__

The sum of the first 6 terms is ...

  Sn = a1·(r^n -1)/(r -1)

  S6 = 27·((2/3)^6 -1)/(2/3 -1)

  S6 = 27·(64/729-1)/(2/3-1) = (27)(665)/243 = 73 8/9

The sum of the first 6 terms is 73 8/9.

_____

<em>Check on the sum</em>

The first 6 terms are ...

  27, 18, 12, 8, 5 1/3, 3 5/9

Their sum is 73 8/9, as above.

8 0
3 years ago
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