I can buy 75 latex balloons and 50 mylar balloons.
This is a problem from an algebraic equation. We can solve this problem by following a few steps.
We need 125 balloons. Let's assume we have to purchase x latex balloons.
So, mylar balloons are ( 125 - x ).
Our total budget is $32.50.
The cost of x latex balloons is ($.10 × x) = $.10x , as the latex balloons cost $.10 each.
The cost of ( 125- x) mylar balloons is $[( 125- x) × 0.50] , as the mylar balloons cost $.50 each.
So the total cost is,
$[( 125- x) × 0.50] + $.10x = 32.50
Now, we have to solve this equation, Let's simplify it.
62.50 - 0.50x + .10x = 32.50
Or, 62.50 - 0.40x = 32.50
Or, -0.40x = 32.50 - 62.50 [ deduce 62.50 from both side ]
Or, -0.40x = -30 [ we should devide both sides 0.40 ]
Or, x = 30/0.40 = 75
So, the number of latex balloons is 75. Therefore, the number of remaining mylar balloons is ( 125 - 75) = 50
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