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Gelneren [198K]
1 year ago
7

You are on the prom decorating committee and are in charge of buying balloons. you want to use both latex and mylar balloons. Th

e latex balloons cost $.10 each and the mylar balloons cost $.50 each. You need 125 balloons and you have $32.50 to spend. how many of each can you buy?
Mathematics
1 answer:
Alla [95]1 year ago
5 0

I can buy 75 latex balloons and 50 mylar balloons.

This is a problem from an algebraic equation. We can solve this problem by following a few steps.

We need 125 balloons. Let's assume we have to purchase x latex balloons.

So, mylar balloons are ( 125 - x ).

Our total budget is $32.50.

The cost of x latex balloons is ($.10 × x) = $.10x , as the latex balloons cost $.10 each.

The cost of ( 125- x)  mylar balloons is $[( 125- x) × 0.50] , as the mylar balloons cost $.50 each.

So the total cost is,

$[( 125- x) × 0.50] + $.10x  = 32.50

Now, we have to solve this equation, Let's simplify it.

62.50 - 0.50x + .10x = 32.50

Or, 62.50 - 0.40x = 32.50

Or, -0.40x =  32.50 - 62.50       [ deduce 62.50 from both side ]

Or, -0.40x =  -30                 [ we should devide both sides 0.40 ]

Or, x = 30/0.40 = 75

So, the number of latex balloons is 75. Therefore, the number of remaining mylar balloons is ( 125 - 75) = 50

To know more about algebraic equations visit,

brainly.com/question/20380548?referrer=searchResults

#SPJ9

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