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Gelneren [198K]
1 year ago
7

You are on the prom decorating committee and are in charge of buying balloons. you want to use both latex and mylar balloons. Th

e latex balloons cost $.10 each and the mylar balloons cost $.50 each. You need 125 balloons and you have $32.50 to spend. how many of each can you buy?
Mathematics
1 answer:
Alla [95]1 year ago
5 0

I can buy 75 latex balloons and 50 mylar balloons.

This is a problem from an algebraic equation. We can solve this problem by following a few steps.

We need 125 balloons. Let's assume we have to purchase x latex balloons.

So, mylar balloons are ( 125 - x ).

Our total budget is $32.50.

The cost of x latex balloons is ($.10 × x) = $.10x , as the latex balloons cost $.10 each.

The cost of ( 125- x)  mylar balloons is $[( 125- x) × 0.50] , as the mylar balloons cost $.50 each.

So the total cost is,

$[( 125- x) × 0.50] + $.10x  = 32.50

Now, we have to solve this equation, Let's simplify it.

62.50 - 0.50x + .10x = 32.50

Or, 62.50 - 0.40x = 32.50

Or, -0.40x =  32.50 - 62.50       [ deduce 62.50 from both side ]

Or, -0.40x =  -30                 [ we should devide both sides 0.40 ]

Or, x = 30/0.40 = 75

So, the number of latex balloons is 75. Therefore, the number of remaining mylar balloons is ( 125 - 75) = 50

To know more about algebraic equations visit,

brainly.com/question/20380548?referrer=searchResults

#SPJ9

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Answer:

The number of footballs, basketballs and volleyballs were sold are 75, 36 and 15 respectively.

Step-by-step explanation:

Consider the provided information.

A football costs $35, a basketball costs $25  and a volleyball costs $15.

Let F represents the football, B represents the basketball and V represents the volleyball.

On a given day, the store sold 5 times as many footballs as volleyballs.

F=5V......(1)

They  brought in a total of $3750 that day,

35F+25B+15V=3750......(2)

The money made from basketballs alone was 4 times the money.

25B=4(15V)......(3)

By equation 1, 2 and 3.

35(5V)+4(15V)+15V=3750

250V=3750

V=15

Substitute the value of V in equation 1 and 3.

F=5(15)=75

25B=4(15\times 15)\\B=36

Hence, the number of footballs, basketballs and volleyballs were sold are 75, 36 and 15 respectively.

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Aleksandr-060686 [28]

Answer:

The given theorem proves that the door is not a rectangle right now since, the door came out of shape, it can be proved by the Pythagorean theorem. If the length is set to a certain shape, and the width is set to a certain shape, and drawn to diagonals. If solved by the Pythagorean Theorem, if the length of two diagonals are similar then and only then the door would be a rectangle.

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vekshin1

Answer:

Step-by-step explanation:

Start

<F = <Q                     Given

<GPF = <RPQ           Vertically opposite angles

<FGP = <QRP            A triangle has 180 degrees. 2 equal angles means the third pair must be equal

Triangle GPF ~ Triangle RPQ   AAA

end

I don't see any way to make these triangles similar except by stating the statement and why it is so. There really are no yes / no choices. If you get another answer, choose it.

20

JL/LE = 90/27                 Given

KL /LD = 90/27               Given

<JLK = <DLK                   Vertically opposite

Are the ratios equal       Yes  Then is the angle included Yes

Then the triangles are similar.

Are the ratios not equal  No then the triangles cannot be similar

Is the angle not included  Then similarity cannot be proved.

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Read 2 more answers
Find the value of cos 28°​cos 62°​– sin 28°​sin 62°​
Romashka [77]
<h2>Answer:</h2>

cos 28°​cos 62°​– sin 28°​sin 62°​ = 0

<h2>Step-by-step explanation:</h2>

From one of the trigonometric identities stated as follows;

<em>cos(A+B) = cosAcosB - sinAsinB             -----------------(i)</em>

We can apply such identity to solve the given expression.

<em>Given:</em>

cos 28°​cos 62°​– sin 28°​sin 62°​

<em>Comparing the given expression with the right hand side of equation (i), we see that;</em>

A = 28°

B = 62°

<em>∴ Substitute these values into equation (i) to have;</em>

<em>⇒ cos(28°+62°) = cos28°cos62° - sin28°sin62°</em>

<em />

<em>Solve the left hand side.</em>

<em>⇒ cos(90°) = cos28°cos62° - sin28°sin62°</em>

⇒ 0 = <em>cos28°cos62° - sin28°sin62°     (since cos 90° = 0)</em>

<em />

<em>Therefore, </em>

<em>cos28°cos62° - sin28°sin62° = 0</em>

<em />

<em />

8 0
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