The mass of sodium sulphate, Na₂SO₄, required to prepare the solution is 10.65 g
<h3>How to determine the mole of sodium sulphate Na₂SO₄</h3>
- Volume = 250 mL = 250 / 1000 = 0.25 L
- Molarity = 0.3 M
Mole = Molarity x Volume
Mole of Na₂SO₄ = 0.3 × 0.25
Mole of Na₂SO₄ = 0.075 mole
<h3>How to determine the mass of sodium sulphate Na₂SO₄</h3>
- Molar mass of Na₂SO₄ = 142.05 g/mol
- Mole of Na₂SO₄ = 0.075 mole
Mass = mole × molar mass
Mass of Na₂SO₄ = 0.075 × 142.05
Mass of Na₂SO₄ = 10.65 g
Thus, 10.65 g of Na₂SO₄ is needed to prepare the solution.
Learn more about molarity:
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Covalent since they are both non metals, a metal and a non metal make an ionic bond
Answer:
That means Cu2O is limiting reagent and C is excess reagent
Explanation:
Based on the reaction, 1 mole of Cu2O reacts per mole of C. The ratio of reaction is 1:1.
To solve this question we need to convert the mass of each reactant to moles. The reactant with the lower amount of moles is limiting reactant and the excess reactant is the reactant with the higher number of moles.
<em>Moles Cu2O -Molar mass: 143.09 g/mol-</em>
114.2g Cu2O * (1mol / 143.09g) = 0.798 moles Cu2O
<em>Moles C -Molar mass: 12.01g/mol-</em>
11.1g C * (1mol / 12.01g) = 0.924 moles C
<h3>That means Cu2O is limiting reagent and C is excess reagent</h3>
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Answer:
0.3 Coulomb charge flows through the toy car.
0.9 Joules of energy is lost by the battery
Explanation:
a)
Current drawn from the battery = 0.50 mA = (0.50 × 0.001 A)
milli Ampere = 0.001 Ampere
Duration of time current drawn = T = 10 min = 10 × 60 s = 600 s
1 min = 60 seconds
Charge flows through the toy car be Q
0.3 Coulomb charge flows through the toy car.
b)
Voltage of the battery = V = 3.0 V
Current drawn from the battery = 0.50 mA = (0.50 × 0.001 A)
Duration of time current drawn = T = 10 min = 10 × 60 s = 600 s
H = 0.9 Joules
0.9 Joules of energy is lost by the battery
