Answer:
14.2L at STP
Explanation:
Based on the problem, 2 moles of NH3 produce 6 moles of HF. To solve this question we have to convert the mass of NH3 to moles. With the chemical equation find the moles of HF and using PV = nRT find the liters of HF:
<em>Moles NH3 -Molar mass: 17.031g/mol-</em>
3.6g NH3 * (1mol / 17.031g) = 0.211 moles NH3
<em>Moles HF:</em>
0.211 moles NH3 * (6mol HF / 2mol NH3) = 0.634 moles HF
<em>Volume HF</em>
PV = nRT; V = nRT/P
<em>Where V is volume in liters, n are moles of the gas = 0.634 moles, R is gas constant = 0.082atmL/molK, T is absolute temperature = 273.15K at STP and P is pressure = 1atm at STP.</em>
Replacing:
V = 0.634moles*0.082atmL/molK*273.15K / 1atm
V = 14.2L at STP
<h3><u>Answer</u>;</h3>
H2O -Bronsted Acid
<h3><u>Explanation;</u></h3>
- Bronsted-Lowry acids are H+ donors
, while Bronsted-Lowry bases are H+ acceptors
.
- A reaction of a Bronsted-Lowry acid and a Bronsted base is a neutralization reaction that is characterized by H+ transfer.
- The above reaction is an example of base ionization or dissociation where;
B (aq) + H2O (l) → BH+ (aq) + OH– (aq)
That is; Base + Acid will give a conjugate acid + hydroxide ion
- In our case; NO2- + H2O → HNO2 + OH- ; H2O is the H+ donor and thus, it is a Bronsted Acid.
Law of electrolysis was given by Faraday.
He discovered that,the amount of chemical change or decomposition is exactly proportional to the quantity of electricity that passes in solution,
When you walk, you push against the floor, and t<span>he floor pushes back against you.
Answer: B. The floor pushes back agaisnt you.
Good luck with your studies, I hope this helps~!
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The answer:
all that we search for is the number of mole of HCl and the number of mole of C2H6O
M(HCl) = 5.5g/ mole of HCl , so mole of HCl = 5.5/M(HCl), where M(HCl) is the molar mass.
M(HCl) = 1+ 36.5= 37.5
moles of HCl = 5.5/37.5=0.14
M(C2H6O) = 200g / moles of C2H6O, so moles of C2H6O=200g / M(C2H6O)
M(C2H6O)= 2x12+ 6 + 16=46,
moles of C2H6O=200g / 46 =<span>4.35 </span><span> moles
</span>
the sum of the moles is 0.14 + <span>4.35 </span> = 4.501 moles
finally, <span>The mole fraction of hcl in a solution prepared by dissolving 5.5 g of hcl in 200 g of c2h6o is 0.031
</span>
because it can be found by 0.14 / 4.501= 0.031
