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Tema [17]
3 years ago
8

Which structures function mainly in transport

Chemistry
1 answer:
Brut [27]3 years ago
5 0
I think the correct answer is D

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What are the functions of corporate management?
Maurinko [17]

Answer:

The four primary functions of managers are planning, organizing, leading, and controlling. By using the four functions, managers work to increase the efficiency and effectiveness of their employees, processes, projects, and organizations as a whole.

5 0
3 years ago
Which of the following suggests that a physical change has taken place in an ice cube
zaharov [31]
The melting of the ice cube indicates physical change has taken place
7 0
3 years ago
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) What is the max
jolli1 [7]

<u>Answer:</u> The mass of aluminium chloride that can be formed are 46.3 g

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}  ....(1)  

  • <u>For Aluminium:</u>

Given mass of aluminium = 32 g  

Molar mass of aluminium = 26.98 g/mol

Putting values in above equation, we get:  

\text{Moles of aluminium}=\frac{32g}{26.98g/mol}=1.186mol

  • <u>For Chlorine:</u>

Given mass of chlorine = 37 g  

Molar mass of chlorine = 71 g/mol

Putting values in above equation, we get:  

\text{Moles of chlorine gas}=\frac{37g}{71g/mol}=0.521mol

For the given chemical equation:

2Al(s)+3Cl_2(g)\rightarrow 2AlCl_3(s)

By Stoichiometry of the reaction:

3 moles of chlorine gas is reacting with 2 moles of aluminium.

So, 0.521 moles of chlorine gas will react with = \frac{2}{3}\times 0.521=0.347moles of aluminium.

As, given amount of aluminium is more than the required amount. Thus, it is considered as an excess reagent.

So, chlorine gas is considered as a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

3 moles of chlorine gas is producing 2 moles of aluminium chloride

So,  0.521 moles of chlorine gas will react with = \frac{2}{3}\times 0.521=0.347moles of aluminium chloride.

Now, calculating the mass of aluminium chloride by using equation 1, we get:

Moles of aluminium chloride = 0.347 moles

Molar mass of aluminium chloride = 133.34 g/mol

Putting all the values in equation 1, we get:

0.347mol=\frac{\text{Mass of aluminium chloride}}{133.34g/mol}\\\\\text{Mass of aluminium chloride}=46.3g

Hence, the mass of aluminium chloride that can be formed are 46.3 g

7 0
4 years ago
How many moles are in a sample of 1.52 x 1024 atoms of mercury (Hg)?
OLEGan [10]

The answer is:

2.5 moles

The explanation:

when avogadro's number = 6.02 * 10^23

and when 1 mole of the sample will give → 6.02*10^23 atoms

So,        ??? mole of the sample will give→ 1.52 x 10^24 atoms

∴ number of moles = (1.52 X 10^24) * 1 mole / (6.02X10^23)

                                = 2.5 moles

8 0
3 years ago
A substance was analyzed in a laboratory. It was composed of three elements in a fixed ratio. The substance is an ?
Julli [10]
The element strontium (atomic number = 38) has four naturally-occurring isotopes. They are: Isotope / Percent Abundance / Mass (amu) Sr-84 / 0.56% / 83.9134 Sr-86 / 9.86% / 85.9093 Sr-87 / 7.00% / 86.9089 Sr-88 / 82.58% / 87.9056 The first thing to do is to convert all of the percentages to decimal fractions. To do that just move the decimal point two places to the left. Be careful, though...if the decimal is already at the front of the number you STILL have to move it two places. Add leading zeroes as necessary. 0.56% becomes 0.0056 9.86% becomes 0.0986 7.00% becomes 0.0700 82.58% becomes 0.8258 Next multiply each of the decimal fractions by the mass of each isotope. 0.0056 x 83.9134 = 0.47 0.0986 x 85.9093 = 8.47 0.0700 x 86.9089 = 6.08 0.8258 x 87.9056 = 72.59 Finally add the results to find the average atomic mass. 0.47 + 8.47 + 6.08 + 72.59 = 87.61 amu This agrees closely with the listed atomic mass for strontium, so I know I probably did my work correctly. I hope that helps
3 0
4 years ago
Read 2 more answers
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