Question

Given the line segment AB with endpoints (-10,0) and (6,8). Find the approximate value of AB, round the answer to the nearest tenth if necessary. Then find the exact coordinates of its midpoint.

Answer 1

The line segment AB with endpoints (-10,0) and (6,8). The equation of the line segment is x-2y+10=0.

Given that,

The line segment AB with endpoints (-10,0) and (6,8).

We have to find the equation of the line segment.

The equation of the line formula is y-y₁=m(x-x₁).

Here we don't know the m value that is nothing but slope of the line.

First we have to find the slope of the line segment.

Slope of the line m=$\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$

m=(8-0)/(6+10)

m=8/16

m=1/2

Now,

We know the equation of line is y-y₁=m(x-x₁)

y-0=1/2(x+10)

2y=x+10

x-2y+10=0

Therefore, The equation of the line segment is x-2y+10=0.

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