Answer:
x=1
Step-by-step explanation:
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Slope is rise/run
so, you go up 4 times and run across 3 times, this is a positive slope, so the slope is
slope: 4/3
the y-intercept is the line that passes the y-axis, (0, -5),
y-intercept: -5
put it together
4/3x-5
Answer:
B Step-by-step explanation:
