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Ksenya-84 [330]

3 years ago

12

Allen's unpaid credit card balance was $3,426.67 his APR is 16.8% what is his new balance after he makes one new transaction for

$235

2 answers:

gayaneshka [121]3 years ago

5 0

Your answer would be $3,395.00. Hope this helps! :)

Nina [5.8K]3 years ago

3 0

New balance
3,426.67+3,426.67×(0.168
÷12)+235=3,709.64

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If x and y are different numbers from 1-50 what is the greatest possible value for (x+y)/(x-y)

fiasKO [112]

Answer:

99

Step-by-step explanation:

Evaluate (x+y)/(x-y) for greatest possible value with the following constraints:

x ≠ y

1 ≤ x ≤ 50

1 ≤ y ≤ 50

To achieve greatest possible value:

Numerator should be as large as possible.

Denominator should be as small as possible without being negative.

x = 50

y = 49

= (50 + 49)/(50 - 49)

= 99/1 = 99

5 0

3 years ago

3. Evaluate the expression. If k = 3 and h = 2. (Be sure to show each step)<br> 4k+2(5k-2)-h

faltersainse [42]

Answer:

36

Step-by-step explanation:

Simple:

(4)(3)+2((5)(3)−2)−2

=12+2((5)(3)−2)−2

=12+2(15−2)−2

=12+(2)(13)−2

=12+26−2

=38−2

=36

5 0

3 years ago

Helpppppp pleaseeee anyoneeeee!!!!!

kakasveta [241]

Answer:

<u>Create a function representing number of published articles per month:</u>

$a=12m+60$

Where:

a = total number of articles published
m = number of months
12 = slope = number of articles published per month
60 = y-intercept = number of published articles at the start (month 0)

<u>Now substitute in the values of m to get the a-value:</u>

m = 1 → a = 12(1) + 60 = 72
m = 3 → a = 12(3) + 60 = 36 + 60 = 96
m = 4 → a = 12(4) + 60 = 48 + 60 = 108
m = 9 → a = 12(9) + 60 = 108 + 60 = 168

6 0

3 years ago

0<br>Domain:<br>Range:<br>Function? what is the domain

Anna35 [415]

Answer:

Domain are any value of x that's make y to be defined

7 0

3 years ago

Read 2 more answers

Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

7 0

3 years ago