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2 years ago

T-shirts are regularly priced at $18.00. The sale price is 20% off the regular price. What is the sale price of a T-shirt?

Mathematics

1 answer:

zaharov [31]2 years ago

6 0

Answer:

$14.40 sale price

Step-by-step explanation:

18 x 0.80 = 14.40

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mr Goodwill [35]

The last one is the answer

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2 years ago

This is 2.

Jlenok [28]

Answer: Lionel should be the correct answer.

Step-by-step explanation: When you are talking about age, that means time. Time is continuous, never stopping or slowing down for anyone. Therefore the graph should be continuous.

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3 years ago

The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)

Lemur [1.5K]

Answer:

Cardiac output: $F=0.055 L\s$

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output: $F=\frac{A}{\int\limits^T_0 {c(t)} \, dt}$ ---1

A = 3 mg

$\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt$

Do, integration by parts

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}$

Substitute the value in 1

Cardiac output: $F=\frac{3}{54.49}$

Cardiac output: $F=0.055 L\s$

Hence Cardiac output: $F=0.055 L\s$

4 0

3 years ago

An author receives a contract from a publisher, according to which she is to be paid a fixed sum of $20,000 plus $3.50 for each

Schach [20]

Answer:

The mean of the total payments she will receive is $79,500.

The standard deviation of the total payments she will receive is $14,000.

Step-by-step explanation:

Given : An author receives a contract from a publisher, according to which she is to be paid a fixed sum of $20,000 plus $3.50 for each copy of her book sold. The author judges that her uncertainty about total sales of the book can be represented by a random variable with a mean of 17,000 and a standard deviation of 4,000 books.

To find : The mean and standard deviation of the total payments she will receive ?

Solution :

Let 'x' represent total sales of the book.

Let 'y' represent the payment to the author.

According to question,

The mean of the total payments she will receive is given by,

$\mu_y=20,000+3.50\mu_x$