Answer:
V = 21145.01 mm³
Step-by-step explanation:
Given that:
The radius of the gumball = 30 mm
The radius of the spherical hollow-core = 28 mm
Consider the radius of the gumball to be
and the radius of the spherical hollow-core to be
. Then;
The volume of the gumball can be determined by using the formula of a sphere.


V = 21145.01 mm³
I'll assume the above equation is: 9 - 7x = 7 - 4(2x+3)
* do distributive multiplication
9 - 7x = 7 - 8x - 12
*move like terms
-7x + 8x = 7 - 12 - 9
* solve for x
x = 7 - 21
x = -14
To check, substitute x by its value -14
9 - 7x = 7 - 4(2x+3)
9 - 7(-14) = 7 -4[2(-14) + 3]
9 + 98 = 7 - 4(-28 +3)
107 = 7 - 4(-25)
107 = 7 + 100
107 = 107
6+4• (5-7)^2
(5-7)^2
-2^2
4
6+4+4
=14
Answer:
The lines would intersect at: (6, -4)
Step-by-step explanation:
I graphed both lines.