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jek_recluse [69]

3 years ago

13

Zoe said the best way to estimate 2,498 - 639 is to round each number to the nearest hundred. Sam said the best way to estimate

inks to round each number to the nearest thousand. Who is correct? explain your answer.

1 answer:

kicyunya [14]3 years ago

8 0

Answer:

sam is correct

Step-by-step explanation:

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Passes through (-4,6) and (2,7)

ch4aika [34]

Answer:

13/6

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

4. A recipe for cookies calls for of a cup of sugar per batch. Elena used 5

allsm [11]

the answer is 5 because if 1 cup of sugar per batch and she put in 5 cups of sugar that makes 5 batches

6 0

3 years ago

6= 5r - 14<br> What are the steps you would use to solve the equation?

gregori [183]

6 = 5r - 14
6 + 14 = 5r
20 = 5r
r = 4

7 0

2 years ago

Michelle is building a rectangular landing strip for airplanes .She has material to cover 1/1,500 of a square mile. The landing

ANEK [815]

I think that the missing word here is:
"with the amount of the material that Michelle has"

Let's say that her landing strip is x miles long, then its area would be:

$\frac{1}{6} *x$

We also know how big it is:

$\frac{1}{6} *x= \frac{1}{1 500}$

now, let's multiply both sides by 6:
$\frac{6}{6} *x= \frac{6}{1 500}$
$1 *x= \frac{3}{750}$
$x= \frac{1}{250}$

So the answer is that it would be $x= \frac{1}{250}$ miles wide

3 0

3 years ago

A restaurant chain has two locations in a medium-sized town and, believing that it has oversaturated the market for its food, is

scoray [572]

Answer:

Yes, since the test statistic value is greater than the critical value.

Step-by-step explanation:

Data given and notation

$\bar X_{1}=360000$ represent the mean for the downtown restaurant

$\bar X_{2}=340000$ represent the mean for the freeway restaurant

$s_{1}=50000$ represent the sample standard deviation for downtown

$s_{2}=40000$ represent the sample standard deviation for the freeway

$n_{1}=36$ sample size for the downtown restaurant

$n_{2}=36$ sample size for the freeway restaurant

t would represent the statistic (variable of interest)

$\alpha=0.05$ significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the true mean of revenue for downtown is higher than for freeway restaurant, the system of hypothesis would be:

Null hypothesis: $\mu_{1}\leq \mu_{2}$

Alternative hypothesis: $\mu_{1} > \mu_{2}$

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Determine the critical value.

Based on the significance level $\alpha=0.05$ and $\alpha/2=0.025$ we can find the critical values from the t distribution dith degrees of freedom df=36+36-2=55+88-2=70, we are looking for values that accumulates 0.025 of the area on the right tail on the t distribution.

For this case the value is $t_{1-\alpha/2}=1.66$

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$t=\frac{360000-340000}{\sqrt{\frac{50000^2}{36}+\frac{40000^2}{36}}}}=1.874$

What is the p-value for this hypothesis test?

Since is a right tailed test the p value would be:

$p_v =P(t_{70}>1.874)=0.033$

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean for the downtown revenue restaurant seems higher than the true mean revenue for the freeway restaurant.

The best option would be:

Yes, since the test statistic value is greater than the critical value.

5 0

2 years ago