Answer:
Sum of money invested in corporate bonds = 30,000
Step-by-step explanation:
Total sum = 40,000
The rate of interest for corporate bonds = 10 % = 0.1
The rate of interest for municipal bonds = 6 % = 0.06
Total interest = 3600
Let sum of money invested in corporate bonds = x
The sum of money invested in municipal bonds = 40000 - x
× 0.1 × 1 + (
) × 0.06 × 1 = 3600
(0.1- 0.06)
+ 2400 = 3600
0.04
= 1200
= 30,000
Since x = sum of money invested in corporate bonds
So sum of money invested in corporate bonds = 30000
This is the expression simplified:
diagonal = sqrt(l^ + w^2)
17 = sqrt(10^2 + x^2)
17^2 = 10^2 + x^2
289 = 100 + x^2
189 = x^2
x = sqrt(189) = 13.747
X = 13.75
width is 13.75 inches
F ( x ) = ( 3 x + 6 ) ( 3 x - 6 ) / ( 3 x + 6 ) = 3 x - 6
and for domain : 3 x + 6 ≠ 0
3 x ≠ - 6
x ≠ - 2
anwser graph of 3 x - 6, with discontinuity at - 2
Try this solution:
1. according to the condition

2. for more details see the attached graph.
Answer: [0;+oo)