You just have to try them all:
Y=x+3 ≈ 6=3+3 ≈ 6=6 √
Y=x+3 ≈ 8=4+3 ≈ 8=7 X
So the first function doesn't work
Y=2x ≈ 6=2(3) ≈ 6=6 √
Y=2x ≈ 8=2(4) ≈ 8=8 √
Second function works
Y=x+4 ≈ 6=3+4 ≈ 6=7 X
Third function does not work
Y=12-x ≈ 6=12-3 ≈ 6=9 X
Fourth function doesn't work
So your answer is Y=2X :)
It’s the second one because it can’t be half but it can be 1/4 and if you do the measurements you can tell it is the second one
Answer: 29.28 years
Explanation:
From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body it is revolving about.
P² =A³
Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)
It is given that, For Saturn, A = 9.5 AU. We need to find P
⇒P² = (9.5 AU)³
⇒P² = 857.38
⇒P = 29.28 years
Thus, the orbital period of Jupiter is 29.28 years around the Sun.
Answer:
When the shape reflects about the x-axis, the x-coordinate remains unchanged but the y-coordinate becomes negative. When the shape reflects about the y-axis, the y-coordinate remains the same but the x-coordinate becomes negative.
Step-by-step explanation:
Sample answer from Edmentum
