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FromTheMoon [43]
1 year ago
14

3 Find mLABC. A (50-x) ✓ B 80° (2x + 40)° D

Mathematics
1 answer:
Gnoma [55]1 year ago
4 0

Answer:

∠ ABC = 40°

Step-by-step explanation:

the 3 angles lie on a straight line ABE and sum to 180° , that is

50 - x + 80 + 2x + 40 = 180

x + 170 = 180 ( subtract 170 from both sides )

x = 10

Then

∠ ABC = 50 - x = 50 - 10 = 40°

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Which possibly forms a triangle
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Answer:

C. 17, 12, 7

Step-by-step explanation:

In a triangle, the sum of the lengths of any two sides must be greater then the length of the third side. If you can show any two segments, the sum of whose lengths is less than the length of the third segment, that cannot form a triangle.

In choices A, B, and D, there is at least one sum of the lengths of two segments that is less then the length of the third segment. That shows that choices A, B, and D cannot form triangles.

A. 8 + 7 = 15 < 16 No

B. 9 + 7 = 16 = 16 No

D. 11 + 5 = 16 < 17 No

C.

17 + 12 = 29 > 7

12 + 7 = 19 > 17

17 + 7 = 24 > 12

Yes

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Riley and Francesca both commute to work. Riley's commute on the train
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Makovka662 [10]

Answer:

117° I believe.

Step-by-step explanation:

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3 years ago
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Identify the shape of the cross section that is perpendicular to the base of a cylinder.
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Use the set of data to calculate the measures that follow.
zepelin [54]

Answer:

<h3>Mean=3.5</h3><h3>Median=3.5</h3><h3>Range=6</h3><h3>Interquartile=1</h3>

Step-by-step explanation:

Given set of data is 0, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 6

<h3>To find Mean , Median , Range and Interquartile range :</h3>

First finding Mean

  • Mean=\frac{sum of the observations}{number of observations}
  • =\frac{0+2+3+3+3+3+3+4+4+4+4+5+5+6}{14}
  • =\frac{49}{14}
  • =\frac{7}{2}
  • =3.5
<h3>Therefore Mean=3.5</h3><h3>Median:</h3>
  • Since the number of observations is even, so the meadian becomes
  • Median=\frac{sum of the two mid terms}{2}
  • =\frac{3+4}{2}
  • =\frac{7}{2}
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<h3>Therefore Median=3.5</h3><h3>Range:</h3>
  • Range=greatest value-least value
  • In the given observations we have greatest value is 6 and least value is 0
  • Therefore Range=6-0
<h3>Therefore Range=6</h3><h3>Interquartile:</h3>
  • From the observations we have Q_1=3 and Q_3=4
  • Interquartile=Q_3-Q_1
  • =4-3
<h3>Therefore Interquartile=1</h3><h3 />
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3 years ago
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