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2 years ago

What is the value of the expression below when z=7 6z-2

Mathematics

1 answer:

horsena [70]2 years ago

6 0

Answer:

the answer is 40

Step-by-step explanation:

U multiply then subtract.

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The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

3 0

3 years ago

Read 2 more answers

Drag the coordinates to match the coordinates of each point on the left with the coordinates of its reflection across the x-axis

fredd [130]

Answer:

1. (-2,-7)

2. (3,-9)

3. (7,-2)

4.(-3,9)

Step-by-step explanation:

Since the reflection is across the x-axis, the y-coordinate will be flipped.

Example: (-7,4) would become (-7,-4)

HOWEVER, if the reflection is across the y-axis, the x coordinate will be flipped.

Example: (-7,4) would become (7,4)

6 0

2 years ago

Read 2 more answers

the area of a square sandbox is 83 square feet. to the nearest foot, what is the perimeter of sandbox?

vagabundo [1.1K]

$Area=bh$
$b=base$
$h=height$

Since a square has 4 equal sides, we can √83 to give us each side. This being $9.11 feet$

$perimeter=9.11+9.11+9.11+9.11=36.44$

$Answer: 36$ to the nearest foot

7 0

3 years ago

Solve these simultaneous equations 2x+3y=13 4x-y=-2

Neko [114]

X = 1/2 y = 4 by elimination

6 0

3 years ago

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Which function is negative for the interval [-1, 1]?

Finger [1]

Answer:

Graph number 2

Step-by-step explanation:

See attached image.

8 0

1 year ago