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Fed [463]
1 year ago
5

Find the length of side x in simplest radical form with a rational denominator.60°130°X

Mathematics
1 answer:
iren [92.7K]1 year ago
5 0

We will solve using the law of sines as follows:

\frac{1}{\sin(30)}=\frac{X}{\sin (60)}

Now, we solve for X:

\Rightarrow X=\frac{\sin(60)}{\sin(30)}\Rightarrow X=\sqrt[]{3}

So, the length of X is sqrt(3).

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Answer: 10 1/2 degrees Celsius

Step-by-step explanation:

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I need some help with this question?¿
IgorLugansk [536]
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What precent is 30 is 24
GuDViN [60]

Answer:

80 percent

Step-by-step explanation:

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3 years ago
Which is the solution to the system of equations? y=−3/2x−11/2; 6x+y=−4
cupoosta [38]

Answer:

x= 1/3  and y=−6

Step-by-step explanation:

If you want step by step explanation you can get your explanation from

https://www.mathpapa.com And just type that answer in where it says what do you want to  calculate? type it in that box and it give you step by step but i gave you the answer up top you just need the explanation the explanation is hard to type in here that's why i have you that website :)

4 0
3 years ago
The mean amount spent by a family of four on food per month is $500 with a standard deviation of $75. Assuming that the food cos
JulijaS [17]

Answer:

The probability that a family spends less than $410 per month

P( X < 410) = 0.1151

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given mean of the population = 500 </em>

<em>Given standard deviation of the Population = 75</em>

Let 'X' be the variable in normal distribution

      Z = \frac{x-mean}{S.D}

<em>Given X = $410</em>

<em></em>Z = \frac{410-500}{75} = - 1.2<em></em>

<u><em>Step(ii):-</em></u>

The probability that a family spends less than $410 per month

P( X < 410) = P( Z < - 1.2 )

                  =  0.5 - A( -1.2)

                 = 0.5 - A(1.2)

                = 0.5 - 0.3849  ( ∵from normal table)

                = 0.1151

<u>Final answer:-</u>

The probability that a family spends less than $410 per month

P( X < 410) = 0.1151

6 0
3 years ago
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