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3 years ago

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Mathematics

1 answer:

Rom4ik [11]3 years ago

8 0

Answer:10,950=350x+475y

X=trumpet

Y=trombone

Step-by-step explanation:

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The graphs below have the same shape. Complete the equation of the red graph. Enter exponents using the caret (^); for example,

german

Answer:

f(x) = 1-x^2

Step-by-step explanation:

The graph of f(x) is just shifted down 3 units

A shift down is a subtraction

f(x) = g(x) -3

= 4- x^2 -3

=1-x^2

5 0

3 years ago

Read 2 more answers

Question 9 of 25

tresset_1 [31]

Answer:

One approach to this problem is to obtain the graph for the given equation.

We need to find every intersection those functions have with the axis 'x' and 'y'

starting with g(x)

g(x=0)=0-3, first point (0,-3) it iis the crossing point with 'x' axis

g(x)=0=x-3, second point (3,0) it iis the crossing point with 'y' axis

Lets do the same for f(x)

g(x=0)=0, this leads to the first point (0,0) it iis the crossing point with 'x' axis and also, with the 'y' axis

We dont need to find any other, since always y=x

By plotting we have the attached picture

Now you can see that g(x) differs from its parent function in that is shifted 3 units to the right, and also 3 units down.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

What does - 12/s - 5 - 9w use s =4 and w = 3 equal

qwelly [4]

Your answer would be -35.

5 0

3 years ago

Given that CD¯¯¯¯¯¯¯¯ is a perpendicular bisector of AB¯¯¯¯¯¯¯¯, where D is on AB¯¯¯¯¯¯¯¯, how can you use the Pythagorean Theor

Liula [17]

Answer:

$(AD)^2 + (CD)^2 = (CA)^2$ and $(CD)^2 + (BD)^2 = (CB)^2$

Step-by-step explanation:

Given

Bisector: CD

of Line AB

Required

Apply Pythagoras Theorem

From the question, CD bisects AB and it bisects it at D.

The relationship between AB and CD is given by the attachment

Considering ACD

From the attachment, we have that:

$Hypothenuse = CA$

$Opposite = CD$

$Adjacent = AD$

By Pythagoras Theorem, we have

$(AD)^2 + (CD)^2 = (CA)^2$

Considering CBD

From the attachment, we have that:

$Hypothenuse = CB$

$Opposite = CD$

$Adjacent = BD$

By Pythagoras Theorem, we have:

$(CD)^2 + (BD)^2 = (CB)^2$

4 0

2 years ago

Read 2 more answers

I need help with this problem if you can help please tell me what you did so I can understand please :)

balu736 [363]

The perimeter is 20 units

Step-by-step explanation:

The end-point of a side of square can be used to calculate length of a side. And the side will be used to calculate the perimeter.

Given

(3,-1) and (7,2)

Let

(3,-1) = (x1,y1)

(7,2) = (x2,y2)

We have to calculate the distance

The formula for distance is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let s be the side of a square

then,

$s=\sqrt{(7-3)^2+(2-(-1))^2}\\s=\sqrt{(4)^2+(2+1)^2}\\=\sqrt{16+(3)^2}\\=\sqrt{16+9}\\=\sqrt{25}\\=5\ units$

The side of square is 5 units. Then,

$Perimeter=P=4s\\=5*4\\=20\ units$

The perimeter is 20 units

Keywords: Perimeter, Square

Learn more about perimeter at:

#LearnwithBrainly

6 0

2 years ago