3 years ago

Help please i really need it

Mathematics

1 answer:

mihalych1998 [28]3 years ago

3 0

Answer:

3x - 4

Step-by-step explanation:

Slope (m): 3

Y-intercept (c): = -4

Equation of Line: Y=mx + c

Y=3x -4

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Help me please idk how to do it

frozen [14]

You do £68.85 - £15.30= (the answer)
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5 0

3 years ago

a dvd costs twice as much as a music cd. Jack buys 2 dvds and 2 cds and spends $45. Determine how much one cd costs. in dollars

VMariaS [17]

$dvd=d \\ cd=c \\ \\ \left \{ {{d=2c} \atop {2d+2c=45}} \right. \\ \\ 2(2c)+2c=45 \\ 4c+2c=45 \\ 6c=45 \\ c=7.5 \\ \\ d=2(7.5) \\ d=15$

One CD costs $7.50.
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3 years ago

Read 2 more answers

Identify the "inside function" u = f(x) and the "outside function" y = g(u). Then find dy/dx using the Chain Rule.

skad [1K]

DfLet $f(x)=\sec x$ and $g(x)=\sqrt x$ . Then

$y=\sec\sqrt x=\sec(g(x))=f(g(x))=f\circ g(x)$

By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx}$

where $u=g(x)=\sqrt x$ , so that $y=f(g(x))=f(u)=\sec u$ . We have

$\dfrac{\mathrm du}{\mathrm dx}=\dfrac1{2\sqrt x}$
$\dfrac{\mathrm d\sec u}{\mathrm du}=\sec u\tan u$

and so

$\dfrac{\mathrm dy}{\mathrm dx}=\sec u\tan u\dfrac{\mathrm dy}{\mathrm du}=\dfrac{\sec\sqrt x\,\tan\sqrt x}{2\sqrt x}$