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Lapatulllka [165]
2 years ago
5

Suppose you are solving an inequality. Under what circumstances do you reverse the inequality symbol? Select all that apply.A. a

dding a negative number on both sidesadding a negative number on both sidesB. subtracting a negative number on both sidessubtracting a negative number on both sidesC. multiplying by a negative number on both sidesmultiplying by a negative number on both sidesD. dividing by a negative number on both sides

Mathematics
1 answer:
pantera1 [17]2 years ago
3 0

Answer:

The correct options are C and D

Only multiplication by a negative number and division by a negative number changes the inequality sign

Explanation:

Consider the inequality:

5>2

This is clearly true that 5 is greater than 2

adding a positive number on both sides would not change the inequality sign, because:

\begin{gathered} 5+1>2+1 \\ 6>3 \end{gathered}

6 is truly greater than 3

Same thing goes with subtracting a negative number, it won't change the inequality sign.

Multiplying by a negative number though,

\begin{gathered} 5\times-2>2\times-2 \\ -10>-4 \end{gathered}

This is NOT TRUE, because -10 is less than -4, and hence, we change the inequality sign as

-10

Division by a negative number also changes the inequality sign.

In conclusion, only multtplication by a negative number and division by a negative number changes the inequality sign.

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4 years ago
Which is an equation of the line that contains the points (0,2) (4,0)
alekssr [168]

Answer:

Y= -1/2x+2

Step-by-step explanation:

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (0,2), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=0 and y1=2.

Also, let's call the second point you gave, (4,0), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=4 and y2=0.

Now, just plug the numbers into the formula for m above, like this:

m=

0 - 2

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or...

m=

-2

4

or...

m=-1/2

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-1/2x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(0,2). When x of the line is 0, y of the line must be 2.

(4,0). When x of the line is 4, y of the line must be 0.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=-1/2x+b. b is what we want, the -1/2 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (0,2) and (4,0).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(0,2). y=mx+b or 2=-1/2 × 0+b, or solving for b: b=2-(-1/2)(0). b=2.

(4,0). y=mx+b or 0=-1/2 × 4+b, or solving for b: b=0-(-1/2)(4). b=2.

See! In both cases we got the same value for b. And this completes our problem.

The equation of the line that passes through the points

(0,2) and (4,0)

is

y=-1/2x+2

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