Mr. Parker has 982 pounds of grain. He feeds 240 pounds ro his pigs and 460 to his cows. How much grain does he have left

Mathematics

1 answer:

denpristay [2]3 years ago

3 0

Starting amount: 982 pounds of grain

Since Mr. Parker fed 240 pounds of grain to his pigs, subtract 240 pounds from 982 pounds of grain.

982 - 240 = 742

After feeding pigs: 742 pounds of grain

Mr. Parker fed another 460 pounds of grain to his cows from his 742 pounds, so subtract 460 pounds from 742 pounds.

742 - 460 = 282

After feeding pigs and cows: 282 pounds of grain

Mr. Parker has 282 pounds of grain left.

You might be interested in

Find the slope of the line. <br><br> A. 1/3<br> B. - 1/3<br> C. 3<br> D. -3

BARSIC [14]

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (0, -2) and (6, 0).

Substitute:

$m=\dfrac{0-(-2)}{6-0}=\dfrac{2}{6}=\dfrac{1}{3}$

<h3>Answer: A. 1/3</h3>

3 0

2 years ago

Suppose you have just enough money, in coins, to pay for a gallon of milk priced at $2.40. You have 12 coins, all quarters and d

wel

The answer is
q + d = 12
0.25q + 0.10d = 2.40

q - the number of quarters
d - the number of dimes

You have 12 <span>coins, all quarters and dimes:
q + d = 12

The value of 1 quarter is $0.25.
The value of 1 dime is $0.10.
Therefore, if you want to pay </span>$2.40 you will have q quarters of value $0.25(0.25q) and d dimes of value $0.10d (0.10d).
The second equation is:
0.25q + 0.10d = 2.40

3 0

3 years ago

Shade a model that shows 0.674

Ratling [72]

0.674 means that it 674/1000

which mean that if the model consists of 1000 squares, you have to shade 674 of the squares.

If the model consists of 500 squares, you have to shade 337 of the squares ( you get the number after dividing both 674 and 1000 with 2)

5 0

3 years ago

The average weight of 3 containers A,B and C is 3.2kg. Container A is twice as heavy as container B. Containers B is 400 g heavi

dlinn [17]

Answer:

The weight of container C is 2.1kg.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the weight of container A.

y is the weight of container B.

z is the weight of container C.