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Gre4nikov [31]
2 years ago
15

the starting salaries of individuals with an mba degree are normally distributed with a mean of $40,000 and a standard deviation

of $5,000. what is the random variable in this experiment?
Mathematics
1 answer:
Zepler [3.9K]2 years ago
3 0
ANSWER: Fifty-eight percent of the MBA students will earn at least a $34,000 staring salary.
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What is the least common multiple of the denominatiors for the two fractions 1/6 and 5/8
aksik [14]

Answer:

24

Step-by-step explanation:

6: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60

8: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80

If you list out the multiples of 6 and 8 you will find that the least common multiple is 24.

7 0
4 years ago
100% is 19 of what number?
nikitadnepr [17]

Answer:

Step-by-step explanation:

7 0
4 years ago
Joshua invested $97,000 in an account paying an interest rate of 6% compounded
Harlamova29_29 [7]
Answer:- $154,763.5

6 0
3 years ago
6. Suppose that a fair coin is tossed 2 times, and the result of each toss (H or T) is recorded.
nekit [7.7K]

Answer:

a) S= {HH, HT, TH, TT}

b) P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25

P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5

P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25

And we have the following table:

X     |     0   |     1   |      2

P(X) |  0.25 |  0.5 |  0.25

Step-by-step explanation:

Let's define first some notation

H= represent a head for the coin tossed

T= represent tails for the coin tossed

We are going to toss a coin 2 times so then the size of the sample size is 2^2 = 4

a. What is the sample space for this chance experiment?

The sampling space on this case is given by:

S= {HH, HT, TH, TT}

b. For this chance experiment, give the probability distribution for the random variable of the total number of heads observed.

The possible values for the number of heads are X=0,1,2. If we assume a fair coin then the probability of obtain heads is the same probability of obtain tails and we can find the distribution like this:

P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25

P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5

P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25

And we have the following table:

X     |     0   |     1   |      2

P(X) |  0.25 |  0.5 |  0.25

5 0
3 years ago
The bake sale raised $60.00. If each cookie cost $0.75, how many cookies were sold
NARA [144]

Answer:

80cookies

Step-by-step explanation:

60 / .75 = 80cookies

<em>good luck, i hope this helps :)</em>

7 0
3 years ago
Read 2 more answers
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