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Anettt [7]
3 years ago
11

The bake sale raised $60.00. If each cookie cost $0.75, how many cookies were sold

Mathematics
2 answers:
NARA [144]3 years ago
7 0

Answer:

80cookies

Step-by-step explanation:

60 / .75 = 80cookies

<em>good luck, i hope this helps :)</em>

Lubov Fominskaja [6]3 years ago
3 0

Answer:  80 cookies were sold.

Step-by-step explanation:

To solve this, we divide the amount of money they earned by the amount of money each cookie cost. The answer is 80.

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The endpoints of directed line segment PQ have coordinates of P(-7, -5) and Q(5,3). What are the coordinates of point A, on PQ,t
Kamila [148]

Answer:

Therefore the co-ordinate of the point A is (-4,-3)

Step-by-step explanation:

If A(x₁,y₁) and B(x₂,y₂)  is divided by a point in ration m:n internally.

Then the co-ordinate of the point is  (\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_2}{m+n}).

Given two points are P(-7,-5) and Q(5,3).

A point A on PQ, that divides PQ into a ratio of 1:3.

Since the point A lies on the PQ.

Therefore it divides the line segment PQ internally.

Here x₁= -7,y₁= -5 ,  x₂= 5,y₂ =3, m=1,n=3

Therefore the co-ordinate of the point A is

(\frac{5.1+(-7).3}{1+3},\frac{3.1+(-5).3}{1+3})

=(\frac{-16}{4},\frac{-12}{4})

=(-4,-3)

6 0
3 years ago
A particle travels along the x-axis such that its position at time t is given by the function x(t)= 2t^2+t. What is the average
Lapatulllka [165]

Answer:

4: A

Step-by-step explanation:

Mathematically, the average speed over a particular range will be;

f’(b)-f’(a)/(a-b)

In this case; a = 2 and b = 10

So we have the following;

f’(x) = 4t + 1

f’(10) = 4(10) + 1 = 41

f’(2) = 4(2) + 1 = 9

So we have the average speed change as;

(41-9)/(10-2)

= 32/8 = 4

8 0
2 years ago
What numbers round up and down to 600
yaroslaw [1]
The numbers that round up to 600 and have one decimal place are-
599.5
599.6
599.7
599.8
599.9
The numbers that round down to 600 and have one decimal place are-
600.1
600.2
600.3
<span>600.4
As far as numbers with more than one decimal place that round to 600, there is an infinite number. For example, 600.000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000</span>0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000001 rounds down to 600.000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000.
7 0
2 years ago
Read 2 more answers
Expand the given power by using Pascal’s triangle. (9a - 10b)^6
xxMikexx [17]

Answer:

531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

Step-by-step explanation:

                     1                                n=0

                  1      1                            n=1

                 1   2   1                           n=2

                1  3  3  1                          n=3

              1  4  6  4   1                      n=4

             1  5 10 10 5  1                    n=5

           1 6 15 20 15 6 1                   n=6

This is where n is the exponent in

(x+y)^n.

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

Now we want to expand:

(9a-10b)^6 or we we can rewrite as (9a+(-10b))^6.

Let's replace x with (9a) and y with (-10b) in the expansion:

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

((9a)+(-10b))^6

=1(9a)^6+6(9a)^5(-10b)+15(9a)^4(-10b)^2+20(9a)^3(-10b)^3+15(9a)^2(-10b)^4+6(9a)(-10b)^5+1(-10b)^6

Let's simplify a bit:

=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6

=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

8 0
3 years ago
ABC is a straight line where BC = 3AB. OA = a, AB = b Express OC in terms of a and b.​
Aleks [24]
That would be 3AB because of the expression you have
7 0
2 years ago
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