This problem is solved by using the compound interest formula:
A=P(1+(I/period))^(number of periods)
Where A = amount accumulated and P = amount loaned and I = Interest
A = ? P = $2, 000, I = 0.115, Period = 2 (semi annually) Number of period = 2
*7 (I. e paid twice over a 7 yrs span)
So we have
A = 2000 ( 1 + 0.115/2)^(14)
A = 2000 ( 1 + 0.0575)^(14)
A = 2000 (1.0575)^(14)
A = 2000 (2.1873851765154) = 4374.77035
So we have 4374.80 to the nearest cent.
The danger temperature zone is a range between 40°F and 140°F. My guess would be 41°F
