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otez555 [7]
3 years ago
12

What is the value of y? Enter your answer in the box

Mathematics
2 answers:
melomori [17]3 years ago
7 0
ANSWER

The value of y is
5

EXPLANATION

The given triangle is isosceles.

The base angles are 75° each.

The sum of the interior angles must be 180°

This implies that,

4y + 10 + 75 + 75 =180 \degree

We simplify to get,

4y + 160 = 180

We group like terms to get,

4y = 180 - 160
This will give us,

4y = 20

We divide through by 4 to get,

y = 5

igor_vitrenko [27]3 years ago
5 0

Answer:

The value of Y is 5.

Step-by-step explanation:

I am assuming you're asking of this particular question?

If so, start out by creating a theory that if both sides of the triangle are marked as "equal" with one mark, then both angles of B and C should be equal as well. So, in other words, <em>75</em> = <em>(3x)</em>. Or, in more simpler terms, 75 = 75.

With that in mind, we'll now add all angles to equal 180 since this shape is a triangle. 75 + 75 + (4y+10) = 180.

Add similar terms, 150 + (4y+10) = 180.

Subtract 150 from both sides; (4y+10) = 30.

Subtraction Property of Equality (Subtract 10 from both sides); 4y = 20.

Finally, divide both sides by 4. Y = 5.

    <em>I hope this helped</em>~♥

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Answer:

The expressions which equivalent to  (2)^{n+3} are:

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Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = 2^{4}

∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

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Step-by-step explanation:

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Step-by-step explanation:

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