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Artemon [7]
1 year ago
8

For a moving object, the force acting on the object varies directly with the object's scceleration. When a force of 90 N acts on

a certain object, the acceleration of the ebject is 9m^(2)s^(2), If the force is changed to 100N, what will be the acceleration of the object?
Mathematics
1 answer:
andrezito [222]1 year ago
7 0

The acceleration if the object when force is 100N is 10 meters per seconds squared

<h3>How to find the acceleration of the object</h3>

Given the direct variation relationship

force , f α acceleration, a

f = ka

k = constant of variation

solving for k

90 = k * 9

k = 90/9

k = 10

when force is 100N

100 = 10 * a

a = 100 / 10

a = 10

Learn more about acceleration here:

brainly.com/question/25749514

#SPJ1

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Classify each real number. List all the subsets in which the number belongs.
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Answer:

Step-by-step explanation:

1-integer

2-rational

3-whole

4- irrational

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The figure is made up of a cylinder and a half sphere. What is the volume of the composite figure? Use 3.14 for Pi. Round to the
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Step-by-step explanation:

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3 years ago
The four digit numeral 3AA1 is divisible by 9. What digit does A represent
dexar [7]

Answer:

A = 2, the number is 3221

Step-by-step explanation:

In order for the number to be divisible by 9, the sum of it's digit has to be divisible by 9.

In our case, 4+A+A+1= 9k where k is an integer. the easiest way happens when k=1

5+2A= 9 \rightarrow 2A=4 \rightarrow A = 2

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4 0
2 years ago
License plates in a particular state consist of 4 digits followed by 2 uppercase letters
zubka84 [21]

Answer:

2,620,800  license plates can there be in this state if the first digit cannot be 2, and repetition of letters and numbers is not permitted.

Step-by-step explanation:

Here the licence plate has 4 numbers and 2 uppercase letters.

Given: The first two numbers CANNOT be 2.

           Repetition in NOT permitted.

Now, according to the question:

The available options in the first number = Any number other then 2

= <u>9 options.</u>

The available options in the Second  number = Any number other then 2  and the first number as  Repetition in NOT permitted.

= <u>8 options.</u>

The available options in the Third  number = Any number other then first     and second  number as  Repetition in NOT permitted.

= <u>8 options</u>

The available options in the Fourth number = Any number other then first     second and third number as  Repetition in NOT permitted.

= <u>7 options</u>

The available options in the Fifth place Alphabet =<u> 26 options</u>

The available options in the Fifth place Alphabet = Any number other then first alphabet  Repetition in NOT permitted.

<u>= 25 options</u>

<u />

So, the total number of options =   PRODUCT OF ALL POSSIBLE OPTIONS

= 9 x 8  x 8 x 7 x 26 x 25

= 2,620,800 options.

Hence, 2,620,800  license plates can there be in this state if the first digit cannot be 2, and repetition of letters and numbers is not permitted.

4 0
4 years ago
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