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Artemon [7]
1 year ago
8

For a moving object, the force acting on the object varies directly with the object's scceleration. When a force of 90 N acts on

a certain object, the acceleration of the ebject is 9m^(2)s^(2), If the force is changed to 100N, what will be the acceleration of the object?
Mathematics
1 answer:
andrezito [222]1 year ago
7 0

The acceleration if the object when force is 100N is 10 meters per seconds squared

<h3>How to find the acceleration of the object</h3>

Given the direct variation relationship

force , f α acceleration, a

f = ka

k = constant of variation

solving for k

90 = k * 9

k = 90/9

k = 10

when force is 100N

100 = 10 * a

a = 100 / 10

a = 10

Learn more about acceleration here:

brainly.com/question/25749514

#SPJ1

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Find the domain and range of the exponential function h(x) = –343x.
Amanda [17]

The function is supposed to be;

h(x) = -343^(x)

Answer:

The domain will be a set of real numbers while the range will be y ≤ 0 and on the interval (-∞, 1)

As x is increasing, h is decreasing and as x is decreasing, h is increasing

Step-by-step explanation:

We are given the function as;

h(x) = -343^(x)

The formula is;

y = a^(x) since it's symmetrical to the x-axis

However in this case;

y = -a^(x)

Now, the domain is y and the range is a set of values of x.

I've attached a graph of this function drawn on desmos.

From the graph we can see that The domain will be a set of real numbers while the range will be on the interval (-∞, 1)

For a value of x = 0,we have;

h(0) = -343^(0)

h(0) = -343

When we increase the value of x to 3,we have;

h(3) = -343^(3)

h(3) = -40353607

When we decrease the value of x to -3, we have;

h(-3) = -343^(-3)

h(-3) = 0.00000002478

Thus, we can conclude that;

As x is increasing, h is decreasing and as x is decreasing, h is increasing

4 0
3 years ago
Identify PR rounded to the nearest tenth. Please help asap!!
kicyunya [14]

Trigonometric Functions:

S\frac{O}{H} C\frac{A}{H} T\frac{O}{A}

Sine\frac{Opposite}{Hypotenuse} Cos\frac{Adjacent}{Hypotenuse} Tan\frac{Opposite}{Adjacent}

You have the angle and the adjacent. You need to find the hypotenuse (PR). Therefore, you use cos.

Cos(26)=\frac{13}{H}

Rearrange the formula to find H (PR):

H = \frac{13}{Cos(26)}

14.463 ~ 14.5

<h2>14.5°</h2>
5 0
3 years ago
According to the data set, where should the
tester [92]

Answer: 59

Step-by-step explanation:

4 0
2 years ago
The value of the function f(x) = 3x squared minus 2x for x =4
goldenfox [79]

Answer:

Answer is 40.

Step-by-step explanation:

7 0
3 years ago
Please help tysm ill mark brainliest
liraira [26]

Answer:

use pemdas(order of the operations)and you'll get the answer 27!!

Step-by-step explanation:

5 0
2 years ago
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