Answer: An adult’s ticket costs $9 while a children’s ticket costs $5.
Step-by-step explanation:
1). 2x + 3y = 33
2). 5x + 2y = 55
3). I’m going to use substitution.
Isolate a variable (x):
2x + 3y = 33
2x = -3y + 33
X = (-3y + 33)/2
X = -3/2y + 33/2
Substitute and solve for y:
5x + 2y = 55
5(-3/2y + 33/2) + 2y = 55
-15/2y + 165/2 + 2y = 55
-11/2y = -55/2
Y = 5 <— children’s ticket.
Solve for x:
2x + 3y = 33
2x + 3(5) = 33
2x + 15 = 33
2x = 18
X = 9 <— adult’s ticket.
Check:
5x + 2y = 55
5(9) + 2(5) = 55
45 + 10 = 55
55 = 55
2x + 3y = 33
2(9) + 3(5) = 33
18 + 15 = 33
33 = 33
Step-by-step explanation:
Question 10 :
3x + 6 = 4x – 12 ( reason: corresponding angles due to parallel lines)
simplify and get x, thus x = 18
to find 3x + 6 or 4x - 12(which is both the same),
3(18) + 6 = 60° , 4(18) - 12 = 60°
Question 11:
2x + 24 + x = 180 ( reason: interior angles due to parallel lines)
simplify again to get x, you will get x = 52
then find the individual by subbing in the value of x into the equation.
so 2x + 24 = 2(52)+24 = 128° and x = 52°
Were are the answer chat ?
Hi there,
368 + 231 = 599
Hope this helps :)
Answer:
The solution for y is y = 2x + 1
Step-by-step explanation:
* <em>Lets explain how to solve an equation for one of the variables</em>
- We need to solve the equation 16x + 9 = 9y - 2 x for y
- That means we want to find y in terms of x and the numerical term
- the equation has two sides, one side contains x and numerical term
and the other side contains y and x
- We need to separate y in one side, and other term in the other side
* <em>Lets do that</em>
∵ 16x + 9 = 9y - 2x
- Add 2x to both sides to cancel -2x from the right side
∴ 16x + 2x + 9 = 9y - 2x + 2x
- Add like terms in each side
∴ 18x + 9 = 9y
- Divide each term by the coefficient of y ⇒ (÷9)
∴ (18 ÷ 9)x + (9 ÷ 9) = (9 ÷ 9)y
∴ 2x + 1 = y
- Switch the two sides
∴ y = 2x + 1
* The solution for y is y = 2x + 1
