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3 years ago

A snow storm dumped 18 7/10 inches of snow in a 12 hour period. How many inches were falling per hour

2 answers:

5 0

All you have to do for this is take your inches (18 7/10 or 18.7) and divide it by the number of hours (12) which makes 1.56in per hour.

Ann [662]3 years ago

4 0

Make 18 7/10 into a improper fraction and multiply that by 12.
Hope this helped.

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AABC is a right triangle. If AC = 15 and BC = 17, find AB.

Schach [20]

Answer:

AC=15

BC=17

AB=?

According to Pythagore's Theorem: AB² + AC² = BC².

AB² = BC² - AC²

= (17)² - (15)²

= 289 - 225

AB² = 64

AB = √(64)

= 8.

So AB = 8.

4 0

3 years ago

Please help!!! Math 10 points!

zheka24 [161]

Answer:

First Blank: 20 photos

Second Blank: 6 minutes

Third Blank: 45 Photos

Fourth Blank: 10 minutes.

Step-by-step explanation:

4*5=20 Photos

30/5=6 Minutes

9*5=45 Photos

50/5=10 Minutes

4 0

3 years ago

Read 2 more answers

Helppp me plsssssssss<br><br>

Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

$\sf \:\:\:\:\:\:\:\:\:\:x_{k}=35$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k}=50$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42$
$\sf \:\:\:\:\:\:\:\:\:\:h=5$

${\bf \:\: {By\:using\:the\: formula}} \\ \\$

$\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\$

$\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\$

${\large{\frak{\pmb{\underline{Additional\: information }}}}}$

MODE

Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

In a frequency distribution the class having maximum frequency is called the modal class.

${\bf{\underline{Formula\:for\: calculating\:mode:}}} \\$

${\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\$

Where,

$\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.$

$\small \blue{ \bigstar}$ $\sf \: f_{k}=frequency\:of\:the\:modal\:class$

$\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class$

$\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class$

$\small \purple{ \bigstar}$ $\sf \: h= width \:of\:the\:class\:interval$

7 0

3 years ago

Samantha has $24 but she wants a pair of Jordan's that are $112. She does chores and she gets paid $5 for each chore. If she doe

natita [175]

Answer:

Check step-by-step.

Step-by-step explanation:

Okay, so. She gets 5 dollars and she does 15 chores. You would multiply it.

5 * 15 = $75

Then you would subtract 112 and 75.

112 - 75 = 37.

She will get $75. Then, she will need to gather $37

6 0

3 years ago

samantha is savung up to bit a car it costs 3000 dollars she has 775 saved up and makes 150 a month how many more monsths will s

zzz [600]

905 or 2045 because I think those are the right answer

7 0

3 years ago