Given data :
a₃ = 9/16
aₓ = -3/4 · aₓ₋₁
Where x is the number of terms ('x' is also written as 'n')
To find the 7th term (a₇):
We know that aₓ = -3/4 · aₓ₋₁
So,
a₃ = -3/4 · a₃₋₁
a₃ = -3/4 · a₂
9/16 = -3/4 · a₂
a₂ = 9/16 × -4/3
a₂ = -36/48
a₂ = -3/4
Again,
aₓ = -3/4 · aₓ₋₁
a₄ = -3/4 · a₄₋₁
a₄ = -3/4 · a₃
a₄ = -3/4 · 9/16
a₄ = -27/64
a₄ = -27/64
For a₅,
aₓ = -3/4 · aₓ₋₁
a₅ = -3/4 · a₅₋₁
a₅ = -3/4 · a₄
a₅ = -3/4 × -27/64
a₅ = 81/256
For a₆,
aₓ = -3/4 · aₓ₋₁
a₆ = -3/4 · a₆₋₁
a₆ = -3/4 · a₅
a₆ = -3/4 × 81/256
a₆ = -243/1024
For a₇,
aₓ = -3/4 · aₓ₋₁
a₇ = -3/4 · a₇₋₁
a₇ = -3/4 · a₆
a₇ = -3/4 × -243/1024
a₇ = 729/4096
Answer:
The value of this would be 3.
Step-by-step explanation:
When you raise something to the third power, it is the same as taking the third root. The third root of 27 is 3.
Solution :
95% confidence interval for the difference between the means of ACT scores between two schools, is given by :
![$[(\overline X_1 - \overline X_2)-ME, (\overline X_1 - \overline X_2)+ME]$](https://tex.z-dn.net/?f=%24%5B%28%5Coverline%20X_1%20-%20%5Coverline%20X_2%29-ME%2C%20%28%5Coverline%20X_1%20-%20%5Coverline%20X_2%29%2BME%5D%24)
M.E. , Margin of error,
= 9.222
s = 3.03
= 1.4
Therefore, 95% CI = [(25.90-27.70) - 1.4 , (25.90-27.70) + 1.4]
= [-3.2, -0.4]
Therefore, the lower bound is -3.2
Answer:
£1430
Step-by-step explanation:
Given data
Principal =£1100
Rate= 5%
time = 6 years
The simple interest formula is
A=P(1+rt)
substitute
A=1100(1+0.05*6)
A=1100(1+0.3)
A=1100(1.3)
A=1100*1.3
A=£1430
Hence the balance is £1430
