25 + 6 - 15 + 25 - 10 + 14 - 21
31 - 15 + 25 - 10 + 14 - 21
16 + 25 - 10 + 14 - 21
41 - 10 + 14 - 21
31 + 14 - 21
45 - 21
24
Now , For 12n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with 5 , it requires at least a single multiple of 5 in its Prime Factors, So 12n cannot end with the digit 0 or 5.
Answer: Hello mate!
The partition of a set is defined as a partition of the set into a nonempty subset, where the set itself is a subset of himself, then the set is a partition of himself.
a) in this we have a set of two objects; A = (1,2) the partitions of this set are: (∅), (1), (2) and (1,2). Where (∅) is the null set.
b) Now we have a set of three objects; B = (a,b,c) the partitions of this set are: (∅), (a), (b), (c), (a,b), (a,c), (b,c), (a,b,c)
There is no value that x cannot be for linear equations.
Thus, the domain is ALL REAL NUMBERS.
CHOICE B.
