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atroni [7]
1 year ago
15

The image shows a portion of the periodic table. Which two elements have similar characteristics?

Chemistry
2 answers:
vekshin11 year ago
7 0
I believe the answer is c but I could be wrong
tia_tia [17]1 year ago
4 0
I believe c because the fluorine and chlorine has they have very similar characteristics
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What is 0.570qt to mL
lutik1710 [3]
539.421ml would be the correct conversion
7 0
4 years ago
The stopcock connecting a 3.06 L bulb containing methane gas at a pressure of 9.61 atm, and a 6.65 L bulb containing oxygen gas
Contact [7]

Answer : The final pressure in the system is 4.22 atm.

Explanation :

First we have to calculate the moles of methane.

PV=n_1RT

where,

P = pressure of gas = 9.61 atm

V = volume of gas = 3.06 L

T = temperature of gas = T

n_1 = number of moles of methane gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

(9.61atm)\times (3.06L)=n_1\times RT

n_1=\frac{29.4}{RT}

Now we have to calculate the moles of oxygen gas.

PV=n_2RT

where,

P = pressure of gas = 1.75 atm

V = volume of gas = 6.65 L

T = temperature of gas = T

n_2 = number of moles of oxygen gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

(1.75atm)\times (6.65L)=n_2\times RT

n_2=\frac{11.6}{RT}

Now we have to determine the final pressure in the system after mixing the gases.

P_{total}=(n_1+n_2)\times \frac{RT}{V_{total}}

where,

P_{total} = final pressure of gas = ?

V_{total} = final volume of gas = (3.06 + 6.65)L = 9.71 L

T = temperature of gas = T

R = gas constant

Now put all the given values in the ideal gas equation, we get:

P_{total}=(\frac{29.4}{RT}+\frac{11.6}{RT})\times \frac{RT}{9.71L}

P_{total}=4.22atm

Therefore, the final pressure in the system is 4.22 atm.

4 0
3 years ago
Use the balanced chemical equation below. How many grams of the product are formed when 2.34 g of sulfur is completely reacted w
levacccp [35]

Answer:

7.89 g

Explanation:

Step 1: Write the balanced equation

S₈ + 16 F₂(g) → 8 SF₄

Step 2: Calculate the moles corresponding to 2.34 g of S₈

The molar mass of S₈ is 256.52 g/mol.

2.34g \times \frac{1mol}{256.52g} = 9.12 \times 10^{-3} mol

Step 3: Calculate the moles of SF₄ produced from 9.12 × 10⁻³ mol of S₈

The molar ratio of S₈ to SF₄ is 1:8. The moles of SF₄ produced are 8/1 × 9.12 × 10⁻³ mol = 0.0730 mol

Step 4: Calculate the mass corresponding to 0.0730 moles of SF₄

The molar mass of SF₄ is 108.07 g/mol.

0.0730 mol \times \frac{108.07 g}{mol} = 7.89 g

7 0
4 years ago
How would you know if this combination is likely to be found in some dirt?
Mkey [24]

Answer:

  very unlikely to be found in dirt

Explanation:

That combination has a ratio of ¹⁴N to ¹⁵N of 10:4 = 2.5: 1. The most ¹⁵N enriched natural material has a ratio of ¹⁴N to ¹⁵N on the order of 250 : 1 or higher. The combination shown is very unlikely to be found in dirt.

6 0
3 years ago
What is compost manure? Explain.​
Goshia [24]

Answer:

Compost is a mixture of organic residues (manure, animal carcasses, straw, etc.) that have been piled, mixed and moistened to undergo thermophilic (high heat 113 to 160 degrees Fahrenheit) decomposition (SSSA, 1997).

Explanation:

4 0
4 years ago
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