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Maurinko [17]
3 years ago
10

Describe all the changes a sample of solid water would undergo when heated from -10degrees c to its critical temperature at a pr

essure of 1.00 atm
Chemistry
1 answer:
masha68 [24]3 years ago
4 0

Answer:Just want to be carefree lately yeah

Explanation: Cradles Profanities

HUSH!

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They will fall at different rates because of air resistance
6 0
3 years ago
Calculate the [H+] in a solution that has a pH of 10.36
Pavlova-9 [17]

Answer:

[H+] = 4.365x10⁻¹¹

Explanation:

The pH is a measurement widely used in chemistry. Is used in quality control to determine if a product is good for human or pet consumption. The equation to obtain the pH is:

pH = -log [H+]

To solve [H+]:

10^pH = -[H+]

10^-pH = -[H+]

In the problem:

10^-10.36 = -[H+]

<h3>[H+] = 4.365x10⁻¹¹</h3>
5 0
3 years ago
Why does oxygen exist as a diatonic molecule and not simply the O atom
Brrunno [24]

Answer:

Oxygen exists as a diatomic molecule in nature when it is not combined with any other element. It forms O2 molecule because it is stable when it is uncombined. It has the lowest energy level when uncombined. ... By achieving octet configuration, the diatomic elements become more stable compared to the single atom.

Explanation:

plsssss.... Mark me as the brainliest

6 0
2 years ago
Calculate the pH of a 0.50 M HIO. The Ka of hypoiodic acid, HIO, is 2.3x10–11.0.305.325.479.474.80
never [62]

Answer:

pH = 5.47

Explanation:

The equilibrium that takes place is:

HIO ↔ H⁺ + IO⁻

Ka = \frac{[H+][IO-]}{[HIO]} = 2.3 * 10⁻¹¹

At equilibrium:

  • [HIO] = 0.5 M - x
  • [H⁺] = x
  • [IO⁻] = x

<u>Replacing those values in the equation for Ka and solving for x:</u>

Ka=\frac{x^2}{0.5-x}=2.3*10^{-11} \\x^2=(2.3*10^{-11})(0.5-x)\\x^2=1.15*10^{-11}-2.3*10^{-11}x\\x^2+2.3*10^{-11}x-1.15*10^{-11}=0\\x=3.39*10^{-6}

Then [H⁺]=3.39 * 10⁻⁶, thus pH = 5.47

7 0
3 years ago
Help with 5b. Full explanation please
larisa86 [58]
Not elementary school work
8 0
3 years ago
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