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Maurinko [17]
3 years ago
10

Describe all the changes a sample of solid water would undergo when heated from -10degrees c to its critical temperature at a pr

essure of 1.00 atm
Chemistry
1 answer:
masha68 [24]3 years ago
4 0

Answer:Just want to be carefree lately yeah

Explanation: Cradles Profanities

HUSH!

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During the winter months, many locations experience snow and ice storms. It is a common practice to treat roadways and sidewalks
Luden [163]

Answer:

The number of moles of CaCO3 on the bag is 112.90 moles

Explanation:

number mole (n) = mass (m) divided by molecular mass (Mm)

Mm of CaCO3 = 100.0869 g/mole

mass in grams = 11.3 Kg x (10^3 g/1 Kg) = 11300 grams

number of moles (n) = 11300 grams divided by 100.0869 grams per mole = 112.90 moles of CaCO3 in the bag.

5 0
3 years ago
3. How many moles of H20 are in 15.2 grams of pure ice?
inna [77]

Answer:

18.01528 grams.

Explanation:

7 0
3 years ago
An organic solvent has a density of 1.31 g/mL. What volume is occupied by 57.5 g of the liquid?
Burka [1]

Answer:

<h3>The answer is 43.89 mL</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question

mass = 57.5 g

density = 1.31 g/mL

We have

volume =  \frac{57.5}{1.31}  \\  = 43.89312977...

We have the final answer as

<h3>43.89 mL</h3>

Hope this helps you

4 0
3 years ago
Need help fast please I am timed and giving 47 points.
Leokris [45]

Answer:

C

Explanation:

6 0
3 years ago
Read 2 more answers
Complete combustion of a 0.600-g sample of a compound in a bomb calorimeter releases 24.0 kJ of heat. The bomb calorimeter has a
coldgirl [10]

The final temperature, t₂ = 30.9 °C

<h3>Further explanation</h3>

Given

24.0 kJ of heat = 24,000 J

Mass of calorimeter = 1.3 kg = 1300 g

Cs = 3.41 J/g°C

t₁= 25.5 °C

Required

The final temperature, t₂

Solution

Q = m.Cs.Δt

Q out (combustion of compound) = Q in (calorimeter)

24,000 = 1300 x 3.41 x (t₂-25.5)

t₂ = 30.9 °C

3 0
3 years ago
Read 2 more answers
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