The value of CE = 18.3
According to the statement
Here we have given the value of tangents AE = 8 and BC = 3
we have to find the value of CE and
It is given that AE is the tangent to the circle.
Now we make a equation to find the CE then
(8)^2 = 3(x+3)
In this equation the value of AE is 8. and
In this x is the value of CE and BC have value 3.
And the total value of BE becomes the 3(x+3) and 3 is the parts by which BE is formed.
Then solve the equation
64= 3x +9
3x = 64-9
x = 18.3
So, The value of CE = 18.3
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Answer:
1- G
2- C
3- G
4- A
Step-by-step explanation:
choose has brainlist
Answer:
n > -6 and n < 8! Heart it if it was helpful :D
Step-by-step explanation:
Okay! So n has to be bigger than -6, but smaller than 8. So the inequalities are n > -6 and n < 8!
So start by putting the negative sign into the second polynomial.
-(6x^2-2x-9)
-6x^2+2x+9
then combine like terms with the first polynomial
5x^3+4x^2-6x^2-2x+9
and you will get
5x^3-2x^2+2x+9
Hope this helps you.
Answer:
You need to be more clearer with the money amount not like 4.20 - 4.50
Step-by-step explanation: