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Kitty [74]
1 year ago
5

Question is in the image. I need help with #19

Mathematics
1 answer:
Naddika [18.5K]1 year ago
6 0

EXPLANATION

Replacing the given functions into the following:

\frac{f(x+h)-f(x)}{h}\frac{x^2-1+h-(x^2-1)}{h}

Removing the parentheses and simplifying:

\frac{x^2-1+h-x^2+1}{h}

Simplifying like terms:

\frac{h}{h}=1

Hence,

\frac{f(x+h)-f(x)}{h}=1

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To answer, we substitute each of the numbers in parentheses to x of h(x) and get the value of g(x).

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Answer:

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

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Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

\frac{f(b)-f(a)}{b-a}

step 1

Find the average rate of change of function h(x) over interval [3,5]

Looking at the third picture (table)

f(a)=h(3)=4  

f(b)=h(5)=16

a=3

b=5

Substitute

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step 2

Find the average rate of change of function f(x) over interval [3,6]

Looking at the graph

f(a)=f(3)=10  

f(b)=f(6)=35

a=3

b=6

Substitute

\frac{35-10}{6-3}=8.33

step 3

Find the average rate of change of function g(x) over interval [2,3]

we have

g(x)=\frac{1}{5}(4)^x

f(a)=g(2)=\frac{1}{5}(4)^2=\frac{16}{5}  

f(b)=g(3)=\frac{1}{5}(4)^3=\frac{64}{5}

a=2

b=3

Substitute

\frac{\frac{64}{5}-\frac{16}{5}}{3-2}=9.6

therefore

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1) Function h

interval [3, 5]

rate of change 6

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interval [3, 6]

rate of change 8.33

3) Function g

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