Need help with number 3

mel-nik [20]

Begin solving like you normally would. Add 2.25 to both sides and subtract 9x from both sides to try getting all x values on one side. However, you will find that after subtracting 9x from both sides, all x values go away, and you end with -2.25=1.6. This is not true (-2.25 is not 1.6), so the answer is no solution. There is no value of x which satisfies that equation.

4 0

3 years ago

An air conditioning system can circulate 470 cubic feet of air per minute. How many cubic yards of air can it circulate per min

vladimir1956 [14]

Answer:

17 yards/minute.

Step-by-step explanation:

7 0

2 years ago

1. Solve log x=4

Helen [10]

1. A. 10,000

Explanation: 10^4 = 10,000

2. x = -12

Explanation: see photo

5 0

3 years ago

Which of the following is not a disadvantage of using cash instead of credit?

sergeinik [125]

The <em>correct answer</em> is:

D) Using cash can make it easier to over-spend since you know exactly how much you have.

Explanation:

Knowing exactly how much you have on hand will actually help you avoid over-spending.

When using cash, you are aware of exactly how much money you have. With a credit card, this may not be the case; this makes it easier with a credit card to spend more money than you should for your budget. With cash it's easier to avoid this problem.

3 0

3 years ago

Read 2 more answers

A manager is comparing wait times for customers in a coffee shop based on which employee is

anyanavicka [17]

Using the t-distribution, as we have the standard deviation for the sample, it is found that there is a significant difference between the wait times for the two populations.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, we test if there is no difference, that is:

$H_0: \mu_A - \mu_B = 0$

At the alternative hypothesis, it is tested if there is difference, that is:

$H_1: \mu_A - \mu_B = 0$

<h3>What are the mean and the standard error of the distribution of differences?</h3>

For each sample, we have that:

$\mu_A = 73, s_A = \frac{2}{\sqrt{100}} = 0.2$

$\mu_B = 74, s_B = \frac{4}{\sqrt{100}} = 0.4$

For the distribution of differences, we have that:

$\overline{x} = \mu_A - \mu_B = 73 - 74 = -1$

$s = \sqrt{s_A^2 + s_B^2} = \sqrt{0.2^2 + 0.4^2} = 0.447$

<h3>What is the test statistic?</h3>

It is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 0$ is the value tested at the null hypothesis.

Hence:

$t = \frac{\overline{x} - \mu}{s}$

$t = \frac{-1 - 0}{0.447}$

$t = -2.24$

<h3>What is the p-value and the decision?</h3>

Considering a one-tailed test, as stated in the exercise, with 100 - 1 = 99 df, using a t-distribution calculator, the p-value is of 0.014.

Since the p-value is less than the significance level of 0.05, it is found that there is a significant difference between the wait times for the two populations.

More can be learned about the t-distribution at brainly.com/question/16313918

8 0

2 years ago