Need help with number 3

What is the length of the hypotenuse of right UVW shown?

photoshop1234 [79]

Answer:

UV

Step-by-step explanation:

8 0

3 years ago

Find an equation for the line tangent to the curve y=x^3-4x+8 at the point (4,56)

Alexxandr [17]

y2(y2−4)=x2(x2−5)y2(y2−4)=x2(x2−5) Multiplying the polynomials gets us to y4−4y2=x4−5x2y4−4y2=x4−5x2. Taking the derivative with respect to xx gets us: 4y3y′−>!8yy′=4x3−10x4y3y′−>!8yy′=4x3−10x. Factoring to get y′y′ by itself: y′(4y3−8y)=4x3−10)y′(4y3−8y)=4x3−10). Divide through to get y′y′ by itself: y′=4x3−10x4y3−8yy′=4x3−10x4y3−8y. You could make your life a bit easier by factoring this into y′=2x(2x2−5)4y(y2−2)y′=2x(2x2−5)4y(y2−2). You could cancel out a factor of 22 to get y′=x(2x2−5)2y(y2−2)y′=x(2x2−5)2y(y2−2). To find the slope, plug in your points x=0,y=−2x=0,y=−2 into our equation for y′y′ to find the slope of the line. Note that the slope is 00. To find the equation of the tangent line, use that value for mm you just found (m=0m=0) and your given points into the point-slope formula and you find that the tangent line is y=−2y=−2.

Thats what my Aunt said... Idk

4 0

3 years ago

Is (x+5) A FACTOR OF f(x) = x3 − 4x2 + 3x + 7

AlekseyPX

Answer:

(x+5) is not a factor of f(x)

Step-by-step explanation:

Step 1 : we solve the equation x +5 = 0

x + 5 = 0 then x = -5

Step 2: we plug in -5 into f(x)

If we get zero then x+5 is a factor of f(x)

If we get a number other than zero then x+5 is not a factor of f(x)

Calculation:

f(-5) = (-5)³ − 4(-5)² + 3(-5) + 7 = - 233

Since we got -233 and not 0

Therefore ,(x+5) is not a factor of f(x)

8 0

2 years ago

Read 2 more answers

A train leaves little rock Arkansas, travels north at 85 kilometers per hour. another train leaves same time and travels south a

iragen [17]

Hi,

Let us denote first train with T₁, its distance d₁, its speed v₁ = 85 km/h.

Similarly, second train would be with T₂, its distance d₂, its speed v₂ = 80 km/h. Also, let d be total distance, d = 495 km.

Given being the fact that train T₁ travels north, and train T₂ travels south, their path is on a straight vertical line. Please create a simple drawing, you will see the vertical line immediately.

Then, we need to find the time t, when d₁ + d₂ = d = 495 km (1)

Each speed v₁, and v₂ is constant, therefore we apply very well known formula:

d₁ = v₁·t, and d₂ = v₂·t (2).

From (1) and (2) we have:

v₁·t + v₂·t = d, or (v₁ + v₂)t = d ⇒ t = d/(v₁ + v₂) = 495/(80 + 85) = 495/165 = 3 hours.

So, it takes 3 hours to have those 2 trains 495 km apart.

Green eyes.

6 0

3 years ago

It has been estimated that only about 30% of California residents have adequate earthquake supplies. Suppose we are interested i

lidiya [134]

Answer: