Ask question

Ask question

All categories

3 years ago

9

X - 3.5 = -3.1 solve for x.

2 answers:

cestrela7 [59]3 years ago

7 0

The answer for this problem is 0.4

uranmaximum [27]3 years ago

6 0

Answer:

0.4

Step-by-step explanation:

The numbers -3.5 and -3.1 have a difference in value of 0.4

An easy way to look at this is to remove the decimal points. 35 - 31 is equal to 4, so that would make the difference 0.4.

Because both numbers are negative, the x must be a positive.

Therefor, 0.4 - 3.5 = -3.1

You might be interested in

Devin made some mistakes. Identify where he made each mistake:

mihalych1998 [28]

When doing the order of operations and you are put in a situation where you do two different operations, solve the problem from left to right.
In this case instead of doing 6*4 first do 24/6 first.

4 0

3 years ago

A triangle has an area of 14 square units. Its height is 7 units. What is the length of its base?

navik [9.2K]

The base should be 4.
Area=1/2* b *h
4*7=28/2=14.

3 0

3 years ago

Simplify the expression 5+(4+x)

photoshop1234 [79]

5 + 4x
I think that’s right

4 0

3 years ago

Read 2 more answers

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

4 0

3 years ago

A negative number raised to an exponent is positive. Which of the following is not true?

Serga [27]

Answer:

the number could be odd.

6 0

3 years ago