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beks73 [17]
1 year ago
11

Word problem on unit rates associated with ratios of whole...

Mathematics
1 answer:
skad [1K]1 year ago
3 0

Given:

a) A color printer prints 17 pages in 6 minutes.

\begin{gathered} 17\text{ pages=6 minutes} \\ 1\text{ minute=}\frac{17}{6}\text{pages} \\ 1\text{minute =2.83 pages} \end{gathered}

A color printer prints 2.83 pages (approximately) per minute.

b) Cheng;s bike cost $40 rent for 8 hours.

\begin{gathered} \frac{x}{1}=\frac{8}{40} \\ x=0.2\text{ hours per dollar} \end{gathered}

Answer: customer

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Lisa starts a different business account that pays simple interest every 1 point
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Interest rate=9%

Step-by-step explanation:

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Rate=315000/35000=9%

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There are 17 camels I want to divide 3 person if the first one belongs 1/2 The second one belongs 1/3 and the third one belongs
Sergio039 [100]

Answer:

  1. 9 camels
  2. 6 camels
  3. 2 camels

Step-by-step explanation:

If I add 1 camel to the herd, the first person can get (1/2)×18 = 9 camels.

The second person gets (1/3)×18 = 6 camels.

The third person gets (1/9)×18 = 2 camels.

The total number of camels distributed is 9+6+2 = 17 camels.

The one remaining is returned to me.

  • 1st person: 9 camels
  • 2nd person: 6 camels
  • 3rd person: 2 camels

_____

<em>Comment on the question</em>

This is a trick question, a joke, a riddle. 17 camels cannot be divided in the given proportions without dividing a camel. The total of camels distributed should be 1/2 +1/3 +1/9 = 17/18 of the herd. Each person actually gets 18/17 of their allotment.

8 0
4 years ago
Daphne likes to ski at a resort that is open from December through April. According to a sign at the resort, 20, percent of the
Arturiano [62]

Answer:

Step-by-step explanation:

From the given information:

We can compute the  null hypothesis & the alternative hypothesis as:

{H_o}:\text{Distribution of snowfalls in her hometown is similar to claimed percentage }

{H_a}:\text{Distribution of snowfalls in her hometown is not similar to claimed percentage }

The degree of freedom = n - 1

The degree of freedom = 5 - 1

The degree of freedom = 4

At the level of significance of 0.05 and degree of freedom 4,

the rejection region = 9.488

However, we can compute the chi-square X² goodness of fit test as:

   

months  frequency (p)  observed O Expected E  Chi-square X^2= \dfrac{(O-E)^2}{E}

Dec          0.2                  16                   16                \dfrac{(16-16)^2}{16} =0      

Jan           0.250             11                   20                \dfrac{(11-20)^2}{20} =4.050      

Feb           0.200             16                  16                 \dfrac{(16-16)^2}{16} =0      

Mar           0.200             18                  16                 \dfrac{(18-16)^2}{16} =0.250

Apr           0.150               19                  12                 \dfrac{(19-12)^2}{12} =4.083

Total            1.000           80                 80                                  8.3833    

∴

The test statistics X² = 8.3833

Thus; we fail to reject the H_o since test statistics X² doesn't fall in the rejection region.

Therefore; there is sufficient evidence to conclude that the distribution of snowfalls in her hometown is not similar to the claimed percentage.

6 0
3 years ago
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