All categories

1 year ago

If 3/4 is the dividend and -2/5 is the divisor then what is the quotient ?

Mathematics

1 answer:

Alexxx [7]1 year ago

4 0

Answer:

$\dfrac{-15}{8}$

Step-by-step explanation:

<h3>Fraction division:</h3>

$\sf \dfrac{3}{4} \ \div \dfrac{-2}{5}$

Use KCF method.

Keep the first fraction.
Change division to multiplication
Flip the second fraction.

$\sf \dfrac{3}{4} \ \div \dfrac{-2}{5}=\dfrac{3}{4}*\dfrac{-5}{2}$

$\sf = \dfrac{3*(-5)}{4*2}\\\\ =\dfrac{-15}{8}$

You might be interested in

What is the exact value of cotangent (StartFraction 3 pi Over 4 EndFraction)? –1 Negative StartRoot 2 EndRoot 1 StartRoot 2 EndR

timurjin [86]

1 negative startroot 2 end root 1 start root 2 end root

6 0

2 years ago

F(t)=t^2-3t<br> g(t)=2t+1<br> find f(g(t))

statuscvo [17]

Answer:

$f (2t + 1) = 4t^{2} - 2t - 2$

7 0

2 years ago

Brielle’s piggy bank has all nickels and dimes. The total value of the money in her piggy bank is $7.80. If Brielle

deff fn [24]

66*0.5=3.30

7.80-3.30=4.50

4.50/0.10=45

ANSWER: 45 dimes

8 0

3 years ago

Hey guys i really need help................. x = 0.5 y = - 1/10

Elanso [62]

Answer:

x=-1/10

y=(-1/10)x0.5

so that y=-1/5

Step-by-step explanation:

8 0

3 years ago

A certain forest covers an area of

iVinArrow [24]

Answer:

2598 square kilometers

Step-by-step explanation:

Hello

Step 1

year one

using a rule of three is possible to find how much is 8.75 od 4500 km2

Let

4500 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4500:100\\x:8.75\\\frac{4500}{100}=\frac{x}{8.75}\\x=\frac{4500*8.75}{100} \\x=393.75\\$

at the end of the year one, the area will be

4500-393.75=4106.25

this will be the initial area for the year 2.

Step 2

repite the step 1 with area initial =4106.25 km2

4106.25 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$4106.25:100\\x:8.75\\\frac{4106.25}{100}=\frac{x}{8.75}\\x=\frac{4106.25*8.75}{100} \\x=359.29\\$

at the end of the year 2, the area will be

4106-359.29=3746.70

this will be the initial area for the year 3.

Step 3

repite the step 1 with area initial =4106.25 km2

3746.70 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3746.70:100\\x:8.75\\\frac{3746.70}{100}=\frac{x}{8.75}\\x=\frac{3746.7*8.75}{100} \\x=327.83\\$

at the end of the year 3, the area will be

3746.70-327.83=3419.09

this will be the initial area for the year 4.

Step 4

year four

repite the step 1 with area initial =3419.09 km2

3419.09 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3419.09:100\\x:8.75\\\frac{3419.09}{100}=\frac{x}{8.75}\\x=\frac{3419.09*8.75}{100} \\x=299.17\\$

at the end of the year 4, the area will be

3419.09-299.173=3119.82

this will be the initial area for the year 5.

Step 5

year five

repite the step 1 with area initial =3119.82 km2

3119.82 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$3119.82:100\\x:8.75\\\frac{3119.82}{100}=\frac{x}{8.75}\\x=\frac{3119.82*8.75}{100} \\x=272.99\\$

at the end of the year 5, the area will be

3119.82-272.99=2846.92

this will be the initial area for the year 6.

Step 6

year six

repite the step 1 with area initial =2846.92km2

2846.92 km2 ⇒ 100$

x?km2 ⇒8.75

do the relation and isolate x

$2846.92:100\\x:8.75\\\frac{2846.92}{100}=\frac{x}{8.75}\\x=\frac{2846.92*8.75}{100} \\x=249.10\\$

at the end of the year six, the area will be

2846.92-249.10=2597.82 square kilometers

Have a great day.

8 0

3 years ago