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n200080 [17]
1 year ago
10

The pair of points (g, -1) and (2, 5) lie on a line with a slope of 3/2. What is the value of g?

Mathematics
1 answer:
Sliva [168]1 year ago
7 0

Answer:

\huge{ \boxed{ \bold{g =  - 2}}}

Step-by-step explanation:

In order to find g we have to use the formula for finding the slope of the line passing through two points that's

m =  \frac{y_2 -y_ 1}{x_2 -x_1 }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are (g, -1) and (2, 5) and m = 3/2

We substitute it into the equation and find g

That's

\frac{3}{2}  =  \frac{5 -  - 1}{2 - g}  \\  \frac{3}{2}  =  \frac{5 + 1}{2 - g }  \:  \:  \:  \:  \:  \:  \:  \frac{3}{2}  =  \frac{6}{2 - g}  \\  \\ 3(2 - g) = 6(2) \\ 6 - 3g = 12 \\  - 3g = 12 - 6 \\  - 3g = 6 \\  \\  \frac{ - 3g}{ - 3}  =  \frac{6}{ - 3}  \\  \\ g =  - 2

We have the final answer as

<h3>g = - 2</h3>

Hope this helps you

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THE table shows the number of pages blaine read for different times. How many pages will blaine read in 42 minutes?
Mkey [24]

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Step-by-step explanation:

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8 0
2 years ago
Match the pairs of values of f(x) and g(x) with the corresponding values of h(x) if h(x) = f(x) ÷ g(x). Tiles f(x) = x2 − 9, and
vitfil [10]
For this case we must solve each of the functions.
 We have then:

 f (x) = x2 - 9, and g (x) = x - 3
 h (x) = (x2 - 9) / (x - 3)
 h (x) = ((x-3) (x + 3)) / (x - 3)
 h (x) = x + 3

 
f (x) = x2 - 4x + 3, and g (x) = x - 3
 
h (x) = (x2 - 4x + 3) / (x - 3)
 h (x) = ((x-3) (x-1)) / (x - 3)
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 f (x) = x2 + 4x - 5, and g (x) = x - 1
 h (x) = (x2 + 4x - 5) / (x - 1)
 h (x) = ((x + 5) (x-1)) / (x - 1)
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 f (x) = x2 - 16, and g (x) = x - 4
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4 0
3 years ago
Read 2 more answers
Triangle DNO has vertices at D(5, 8), N(– 3, 10), and O(– 3, 6). If vertex D is translated 4 units to the right, the best name f
prisoha [69]

Using distance between two points to find the lengths of the edges of the triangle, the correct option is:

b. Isosceles

The distance between two points, (x_1,y_1) and (x_2,y_2), is given by:

d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Vertex D is translated 4 units to the right is (9,8).

The lengths of the edges are:

DN = \sqrt{(9 - (-3))^2 + (8 - 10)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}

DO = \sqrt{(9 - (-3))^2 + (8 - 6)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}

NO = \sqrt{(-3 - (-3))^2 + (10 - 6)^2} = \sqrt{0^2 + 4^2} = 4

<u>Two edges of the same length</u>, hence, it is an isosceles triangle, given by option b.

You can learn more about distance between two points at brainly.com/question/18345417

6 0
2 years ago
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