If I have a 65.56% grade and i get an 80 on a test out of 100, how much will that take it up?

1 answer:

7 0

Well, we need to know the total amount of points you need right now to be with the class, how many points you have, and how many points the test gives

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Use estimation to check the answer to this story problem.

katovenus [111]

Here, the answer would be: 765 * 11 = 8415 [ About 8 thousands ]

In short, Your Answer would be Option C) The answer should be about 8,000 yards. The student's answer is not correct.

Hope this helps!

5 0

3 years ago

Select the expression that makes the equation true.

svetoff [14.1K]

Answer:

a.) -18 x 10^6

Step-by-step explanation:

multiply 9 x-2

add exponents 9 and -3

4 0

3 years ago

Please can u help me

Andreas93 [3]

Step-by-step explanation:

multiply length, width, and height

6x4x6 and 7x4x6

First line: 144cm

Second line: 168cm

and those are the answers

4 0

2 years ago

Read 2 more answers

15. • Solve the simultaneous equations

tamaranim1 [39]

Answer:
B. 1 and -2
Explanation:
First, add up the equations:
x-x+3y+y=4
4y=4
y=1
Now, plug y into any of the original equations above and solve for x:
-x+1=3
-x=2
x=-2
Therefore, the answer is B. 1 and -2

5 0

3 years ago

A restaurant wishes to have at least one server for every 12 tables. Each of the tables in the restaurant seats four guests. If

Fiesta28 [93]

X = number of servers
y = number of guests

$\text {number of guest per table = } 4$ 

 $\text {number of tables = } \dfrac{y}{4}$

 $\text {number of servers needed = } \dfrac{y}{4} \div 12$ 

 $\text {number of servers needed = } \dfrac{y}{4} \times \dfrac{1}{12}$

$\text {number of servers needed = } \dfrac{y}{48}$

There must be at least 1 server for every 12 tables:
$x \geq \dfrac{y}{48}$

8 0

3 years ago