Answer:
The price now is 300$.
Step-by-step explanation:
The problem is related to percentages.
It is provided that the price of meal at a restaurant a couple of decades (20 years) ago was 100$.
Now the price is 200% more than what it was 20 years ago,i.e. the price increased by 200%.
Compute the new price as follows:
![New-Price=100\$+[100\$\times200\%]\\= 100\$+[100\times\frac{200}{100}]\$\\ =100\$+200\$\\=300\$](https://tex.z-dn.net/?f=New-Price%3D100%5C%24%2B%5B100%5C%24%5Ctimes200%5C%25%5D%5C%5C%3D%20100%5C%24%2B%5B100%5Ctimes%5Cfrac%7B200%7D%7B100%7D%5D%5C%24%5C%5C%20%3D100%5C%24%2B200%5C%24%5C%5C%3D300%5C%24)
Thus, the price of the meal now is 300$.
the store is 1/3 the way to her friend's house, not 1/3 mile.
this explains solution:
1/3x = 1/4
x = 1/4 * 1/3
x = 3/4
Notes:
X: is the total distance.
1/3 is the one portion of total distance.
1/4 mile is the distance store.
Answer:
Yes
Step-by-step explanation:
Yes
"What do I want to find out?" is the first step.