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3 years ago

I need to know the answer

Mathematics

1 answer:

Elan Coil [88]3 years ago

8 0

The mistake is n third line - adding 3w
96 + 2w =2(80 - 3w)
96 + 2w = 160 - 6w
+ 6w + 6w
96 + 8w = 160
- 96 -96
8w = 64
w = 8 weeks answer

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Area is 96 length is 4x+8 width is x find x

dimulka [17.4K]

Answer

Step-by-step explanation:

The area would be length times width. x(4x+8) =96

4x^2+8x = 96

4x^2+8x-96=0. We need to factor.

It would be factored to (4x-16)(x+6) = 0

x would be -6 (x+6=0)

or x would be 4 (4x-16=0)

Why would the width be negative?!? So the answer is 4

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3 years ago

AD is the perpendicular bisector of BC. BD = 5x - 10 and DC = 3x + 10. Determine the value of x.

Nookie1986 [14]

Answer: x= 10

Step-by-step explanation:

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3 years ago

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jeka57 [31]

Answer:

=> Apply law of cosine

$c^2=a^2+b^2-2abcos\left(C\right)$

=> input value

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=> simplify

$z=\sqrt{\left(6.5^2+\:9.4^2\right)-\left(6.5\right)\left(9.4\right)\left(-0.65605902899\right)}$

=> calulcation

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2 years ago

Use the given endpoint R and midpoint M of line RS to find the coordinates of the other endpoins.

makvit [3.9K]

S(-6, 4)

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3 years ago

Please help I’ll mark brainliest

denpristay [2]

Answer:

166.27 m2

Step-by-step explanation:

area of hexagon = $\frac{3*\sqrt{3} }{2}$ * $a^{2}$ where a = length of 1 side

this hexagon is made of 6 equivalent triangle

consider ABC triangle

let AC length be x

AB = 2 * AC = 2x = a

$bc^{2} = ab^{2} - ac^{2} \\(4\sqrt{3})^{2} =(2x)^{2} - x^{2} \\48=3*x^{2}\\ 16=x^{2} \\x=4$

Hence a = 8

hence area of hexagon = $\frac{3*\sqrt{3} }{2}$ * $a^{2}$ = $\frac{3*\sqrt{3} }{2}$ * $8^{2}$ = 166.27 m2

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3 years ago