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Pepsi [2]
3 years ago
7

On average, it rains 6 out of 25 days in Houston. On how many days can residents expect rain in 1 year?

Mathematics
1 answer:
zysi [14]3 years ago
5 0

Answer:

87.6 out of 365 so 87 days

Step-by-step explanation:

you divide 365 by 25 and multiply that by 6

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-4y + 8 = 9<br> What dose y equal
Anettt [7]

Answer: y= -1/4

Step-by-step explanation: _4y+8=9

-4Y=1 subtract the 8 (-8) from both sides

divide 4 by both sides and get -1/4

3 0
3 years ago
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What is the value of x
Hunter-Best [27]

Answer:

Depends on the equation

7 0
3 years ago
Which equation represents a hyperbola with a center at (0, 0), a vertex at (−48, 0), and a focus at (50, 0)?
Lerok [7]

bearing in mind that "a" is the length of the traverse axis, and "c" is the distance from the center to either foci.

we know the center is at (0,0), we know there's a vertex at (-48,0), from the origin to -48, that's 48 units flat, meaning, the hyperbola is a horizontal one running over the x-axis whose a = 48.

we also know there's a focus point at (50,0), that's 50 units from the center, namely c = 50.


\bf \textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2}\\ \textit{asymptotes}\quad y= k\pm \cfrac{b}{a}(x- h) \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}


\bf \begin{cases} h=0\\ k=0\\ a=48\\ c=50 \end{cases}\implies \cfrac{(x-0)^2}{48^2}-\cfrac{(y-0)^2}{b^2}=1 \\\\\\ c=\sqrt{a^2+b^2}\implies \sqrt{c^2-a^2}=b\implies \sqrt{50^2-48^2}=b \\\\\\ \sqrt{196}=b\implies 14=b~\hspace{3.5em}\cfrac{(x-0)^2}{48^2}-\cfrac{(y-0)^2}{14^2}=1\implies \cfrac{x^2}{48^2}-\cfrac{y^2}{14^2}=1

8 0
3 years ago
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2/3 of a pizza was left over. A group of friends divided the leftover pizza into pieces equal to 1/18 of the original pizza. Aft
Helen [10]
1/18 devided by 2/3 =


1/18 times 3/2 = 1/12 times 1/6 = 1/72
4 0
3 years ago
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I need to solve this system of equations, how do I do that?<br> 3x-4y=20<br> y=3/4x-5
Paha777 [63]

Answer:

Is is Infinitely many solutions so 0=0

<em><u>Step-by-step explanation:</u></em>

<h3>First we have to rearrange/simplify the equations:</h3>

Equation 1: 4y - 3x = -20

Equation (2):  y - 3x/4  = -5

<h3>Then you remove the fractions by multiplication: </h3>

Multiply equation (2) by 4

<h3>The Equations now look like this: </h3>

Equation 1: 4y - 3x = -20

Equation (2): 4y - 3x = -20

<h3>Solve for y on Equation (2):</h3>

y = <u><em>3x/4 - 5</em></u>

<h3>Then plug in this for the y in Equation 1 and then solve:</h3>

4•(<u><em>3x/4-5</em></u>) - 3x = -20

Therefore the answer leads to:

Infinitely many solutions, 0=0

Hope this helped :')

4 0
3 years ago
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