The percent increase in enrollment is 6 %
The operation used in first step is finding the difference between final value and initial value
<h3><u>Solution:</u></h3>
Given that This year, 1,272 students enrolled in night courses a a local college
Last year only 1,200 students enrolled.
To find: percent increase in the enrollment
The percent increase between two values is the difference between a final value and an initial value, expressed as a percentage of the initial value.
<em><u>The percent increase is given as:</u></em>

Here initial value (last year) = 1200 and final value(this year) = 1272
Substituting the values in above formula,

Thus percent increase is 6 %
Answer:
-7/13
Step-by-step explanation:
The upper quartile is, Q1, is 45. The lower quartile, Q2, is 85. The interquartile range is 40. I hope this helps!
Answer:
10.1 cm
Step-by-step explanation:
1.2 + 0.8 + 2.4 + 1.9 + 1.5 + 2.3 = 10.1 cm
Hey there!
If x = -3 then replace "x" with -3
New equation: -3^-2
(-1 × 3)^-2
(-1 / 3 )× 3
3 × 3 = 3^3 = 9 (Solving for your denominator)
(-1/3)^2
= (1/9)
This your answer is: 1/9
Good luck on your assignment and enjoy your day!
~LoveYourselfFirst:)