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iren [92.7K]
1 year ago
12

u want to construct an open-top box that is 6 inches deep, with a square base. it must have a volume of 864 cubic inches. You ha

ve one big piece of cardboard. You will start by cutting it down to a square, and then you will cut smaller squares out of each corner and fold up the sides.

Mathematics
1 answer:
Arturiano [62]1 year ago
4 0

Let's analyse each sentence:

A)

This sentence is true, because the volume of the box is given and it is 864 in³.

B)

This sentence is false, because the height of the box is given and it is 6 inches.

C)

Let's calculate the sides of the base, knowing that the length and width are the same:

\begin{gathered} V=\text{lwh} \\ 864=l\cdot l\cdot6 \\ l^2=\frac{864}{6} \\ l^2=144 \\ l=^{}12 \end{gathered}

The side of the cardboard will include the length of the base and two times the height, since it will be folded later on, so we have:

\text{cardboard side}=l+2h=12+6\cdot2=24

So the side of the cardboard needs to be 24 inches, so this sentence is false.

D)

This sentence is false, because the height is not equal the length and width.

E)

This sentence is true, because using the variable x to represent the side of the square base (that is, the length and the width), we have:

\begin{gathered} V=l\cdot w\cdot h \\ V=6x^2=864 \end{gathered}

So the correct statements are A and E.

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Elina [12.6K]

Answer:

√(88×11×2×4}=√88²=±88 is your answer

3 0
3 years ago
Read 2 more answers
Please answer correctly, show all steps you did to solve this problem, and i will mark brainliest to best answer
GalinKa [24]

Answer:

Since the values vary from 0.5 to 4.5, let's take 5 intervals of width 1 unit each

(Lower boundary is included, upper boundary is not)

Average

no. of --------> frequency

movies

_______ __________

0 - 1 --------------> 1

1 - 2 --------------> 5

2 - 3 --------------> 5

3 - 4 --------------> 2

4 - 5 --------------> 1

For frequencies, just count the data values in each interval

6 0
3 years ago
Don't know how to solve this problem, help would be appreciated
kenny6666 [7]

Answer:

219

Step-by-step explanation:

The figure has the shape of a trapezoid. We find the area of the trapezoid and subtract the area of the rectangular door.

area of trapezoid = (base1 + base2)h/2

area of trapezoid = (20 ft + 12 ft) * 15 ft / 2

area of trapezoid = 32 ft * 15 ft /2

area of trapezoid = 240 ft^2

area of rectangle = length * width

area of rectangle = 7 ft * 3 ft

area of rectangle = 21 ft^2

area to be painted = area of trapezoid - area of rectangle

area to be painted = 240 ft^2 - 21 ft^2

area to be painted = 219 ft^2

Answer: 219 ft^2

6 0
4 years ago
How do i do this ???
Westkost [7]

a peculiar thing about the centroid of a triangle, is that it cuts all the medians in a 2:1 ratio, so JP : PM are on a 2:1 ratio, thus

\bf JP:PM\qquad 2:1\qquad \cfrac{JP}{PM}=\cfrac{2}{1}\implies \cfrac{27}{PM}=\cfrac{2}{1}\implies \cfrac{27}{2}=PM\\\\-------------------------------\\\\JM=JP+PM\implies JM=27+\cfrac{27}{2}\implies JM=\cfrac{54+27}{2}\\\\\\JM=\cfrac{81}{2}\implies JM=40\frac{1}{2}

4 0
4 years ago
PLEASE HELP QUICK!!
egoroff_w [7]

Answer:

B. (4x+5)(16x2−20x+25)

Step-by-step explanation:

64x3+125

=(4x+5)(16x2−20x+25)

7 0
3 years ago
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