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1 year ago

Hello can someone help I dont really think I'm correct.

Mathematics

1 answer:

nadezda [96]1 year ago

6 0

According to the given number line A is on -7, X is on -2 and E is on 8.

As you can observe in the image below, X is 5 units away from A. At the same time, X is 10 units away from E.

<h2>Therefore, point X is double distant from E as far as it is from A.</h2>

<em>The ratio of this relation would be 2:1 from E to A.</em>

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What is -6(-3+5r)=-5-7r

inna [77]

Answer:

r = 1

Step-by-step explanation:

Use the distributive property to multiply −6 by −3+5r.

18−30r=−5−7r

Add 7r to both sides.

18−30r+7r=−5

Add −30r and 7r to get −23r.

18−23r=−5

Subtract 18 from both sides.

−23r=−5−18

Subtract 18 from −5 to get −23.

−23r=−23

Divide both sides by −23.

r=−23/−23

Divide −23 by −23 to get 1.

r=1

8 0

3 years ago

I need to know the answer.

katrin [286]

Well, apologies if this is wrong but in my opinion, I think it's that The angles do not change. This is because the angles are alright staying in the same place. I don't understand much about angles but it makes the most sense to me.

5 0

3 years ago

(08.06) Data are collected about the amount of time, in minutes, each band member spends practicing. How does a single outlier c

FrozenT [24]

Its A a single outlier causes the upper quartiles to move close together

im pretty sure

7 0

3 years ago

Read 2 more answers

If 2/3(x-6)-3/4x=3 , then x= ?

Elan Coil [88]

Answer:

The value of x for the given expression is - 84

Step-by-step explanation:

Given expression as :

$\frac{2}{3}$ (x - 6) - $\frac{3}{4}$ x = 3

Taking LCM of 3 & 4

So, $\frac{8\times (x-6) - 9x}{12}$ = 3

or, 8 x - 48 - 9 x = 12 × 3

Or, 8 x - 9 x = 36 + 48

or, - x = 84

∴ x = - 84

Hence The value of x for the given expression is - 84 Answer

4 0

3 years ago

Find all solutions to cosx cos3 x-sinx sine3x= 0 on the interval {0,2pi}

fomenos

$\bf \textit{Sum and Difference Identities}
\\ \quad \\
sin({{ \alpha}} + {{ \beta}})=sin({{ \alpha}})cos({{ \beta}}) + cos({{ \alpha}})sin({{ \beta}})
\\ \quad \\
sin({{ \alpha}} - {{ \beta}})=sin({{ \alpha}})cos({{ \beta}})- cos({{ \alpha}})sin({{ \beta}})
\\ \quad \\
\boxed{cos({{ \alpha}} + {{ \beta}})= cos({{ \alpha}})cos({{ \beta}})- sin({{ \alpha}})sin({{ \beta}})}
\\ \quad \\
cos({{ \alpha}} - {{ \beta}})= cos({{ \alpha}})cos({{ \beta}}) + sin({{ \alpha}})sin({{ \beta}})\\\\
------------------------$

$\bf cos(x)cos(3x)-sin(x)sin(3x)=0\implies cos(x+3x)=0
\\\\\\
cos(4x)=0\implies cos^{-1}[cos(4x)]=cos^{-1}(0)\implies 4x=cos^{-1}(0)
\\\\\\
4x=
\begin{cases}
\frac{\pi }{2}\\\\
\frac{3\pi }{2}
\end{cases}\implies 
\begin{cases}
4x=\cfrac{\pi }{2}\implies &\measuredangle x=\cfrac{\pi }{8}\\\\
4x=\cfrac{3\pi }{2}\implies &\measuredangle x=\cfrac{3\pi }{8}
\end{cases}$

5 0

3 years ago