Question

a1" title=" \frac{3}{2x} - \frac{1}{8 {x}^{2} } " alt=" \frac{3}{2x} - \frac{1}{8 {x}^{2} } " align="absmiddle" class="latex-formula">If possible, a step by step for this would help immensely so I could do the rest of the problems like this one.

Answer 1

Problem

Solution

For this case we can take common factor in the denominator 2x and we got:

$\frac{1}{2x}(\frac{3}{1}-\frac{1}{4x})$

Then we can solve the fractions with this operation:

$\frac{1}{2x}(\frac{3\cdot4x-1\cdot1}{1\cdot4x})=\frac{1}{2x}(\frac{12x-1}{4x})$

then we can simplify on this way:

$\frac{12x-1}{6x^2}$