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3 years ago

5

predict the number of blue squares in a quilt with 11 green squares if there are 4 green squares in a quilt with 68 blue squares

2 answers:

Troyanec [42]3 years ago

7 0

68/4=17
17x11=187
There will b 187 blue squares in the quilt

lapo4ka [179]3 years ago

3 0

If you make the numbers into a ratio, it'll be easier to find the answer.
There are 68 blue squares for the 4 green squares in the quilt.
68:4, or 68/4
If we do the division of the ratio, 68/4, we end up with 17.
Now, we multiply that by the 11 green squares of the new quilt.
17x11=187
This shows that there will be 187 blue squares in the quilt with 11 green squares.

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Which graph represents the function y = 3*+2?

puteri [66]

Answer:

We can graph y = 2x/3 - 2 to find the line.

We know one point, which is the y-intercept. The y-intercept is (0,-2) so that is our first point. Plot that point on the chart. Now to find another point, we can just insert a number for x and solve for y. I am going to use the number 3.

y = 2x/3 - 2

y = 2(3)/3 - 2

y = 6/3 - 2

y = 2 - 2

y = 0

So when x = 3 y = 0. We have another point,which is (3,0) Plot the points (0, -2) (3, 0) and draw a line between the points and that is your graph.

there ya go

5 0

2 years ago

If the principal amount of $3,575 earned $1,072 in 3 years find the interest rate

Jlenok [28]

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8 0

3 years ago

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liraira [26]

Answer: 527.79 m²

Step-by-step explanation:

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A = 527.79 m²

6 0

2 years ago

A camera is mounted at a point 4000 feet away from a geyser. If the water is rising vertically at 900 ft/s when it is 3000 feet

Leno4ka [110]

Answer:

$\dot \theta = 0.144\,\frac{rad}{s}$ , $\dot \theta = 8.251\,\frac{deg}{s}$ (Option B)

Step-by-step explanation:

The trigonometric diagram is included herein as attachment. The expression is presented below:

$\tan \theta = \frac{y}{x}$

Where:

$x$ - Horizontal distance between the geyser and the camera.

$y$ - Vertical distance between the geyser and the camera.

The rate of change in terms of time is:

$\dot \theta \cdot \sec^{2}\theta = \frac{\dot y\cdot x-y\cdot \dot x}{x^{2}}$

$\dot \theta \cdot \left(\frac{1}{\cos^{2}\theta} \right) = \frac{\dot y \cdot x - y\cdot \dot x}{x^{2}}$

$\dot \theta = \left(\frac{\dot y \cdot x - y \cdot \dot x}{x^{2}} \right)\cdot \cos^{2}\theta$

$\dot \theta = \left(\frac{\dot y \cdot x - y\cdot \dot x}{x^{2}} \right)\cdot \left(\frac{x^{2}}{x^{2}+y^{2}} \right)$

$\dot \theta = \frac{\dot y \cdot x - y\cdot \dot x}{x^{2}+y^{2}}$

Finally,

$\dot \theta = \frac{\left(900\,\frac{ft}{s} \right)\cdot (4000\,ft)-(3000\,ft)\cdot \left(0\,\frac{ft}{s} \right)}{(4000\,ft)^{2}+(3000\,ft)^{2}}$

$\dot \theta = 0.144\,\frac{rad}{s}$

$\dot \theta = 8.251\,\frac{deg}{s}$

3 0

2 years ago

Find the equation for the line that is parallel to the line with the equation y=−14x−1y=−14x−1 passing through the point (2,0)(2

bezimeni [28]

Use formula: y-y1/x-x1=m(gradient)
so, y=-14x-1
m=-14
y-0/x-2=14/1
y=-14x+28

7 0

3 years ago