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BARSIC [14]
2 years ago
13

Give an example of a polynomial function that meets the above criteria

Mathematics
1 answer:
Komok [63]2 years ago
7 0

Answer:

F(x) = -5x - 8

Explanation:

Let's try with the polynomial function

f(x) = -5x - 8

We can calculate f(8) replacing x by 8, so:

f(8) = -5(8) - 8

f(8) = -40 - 8

f(8) = -48

Additionally, f'(x) will be equal to:

f'(x) = -5

And -5 is distinct from 0.

Finally, if f'(x) = -5, f''(x) is the derivative of a constant, so:

f''(x) = 0 for all x

Therefore, an function that satisfies all the conditions is:

F(x) = -5x - 8

You might be interested in
In ΔVWX, w = 780 cm, ∠V=21° and ∠W=146°. Find the length of x, to the nearest 10th of a centimeter.
wariber [46]

Complete Question

In ΔVWX, w = 780 cm, ∠X =21° and ∠W=146°. Find the length of x, to the nearest 10th of a centimeter.

Answer:

499.9cm

Step-by-step explanation:

We solve for length x using the Sine rule

w/ sin W = x /sin X

Cross Multiply

x × sin W = w × sin X

x = w × sin X/ sin W

x = 780 × sin 21°/ sin 146°

x = 499.88 cm

Approximately to nearest tenth = 499.9cm

8 0
3 years ago
Read 2 more answers
8x2 + 96x + 288 <br> i really need help thanks
Elodia [21]

Answer:

8x² + 96x + 288 = 8(x + 6)²

Step-by-step explanation:

96÷8=12

288÷8=36

8x² + 96x + 288 = 8(x² + 12x + 36)

                           = 8(x² + 2(1)(6)x + 6²)

                           = 8(x + 6)²

7 0
3 years ago
Please help ASAP geometry
lina2011 [118]

Answer:

A' (-6,12)

B' (9,9)

C' (-3,0)

Answered by GAUTHMATH

3 0
3 years ago
A class survey found that 29 students watched television on Monday, 24 on Tuesday, and 25 on Wednesday. Of those who watched TV
gizmo_the_mogwai [7]

Answer:

There were 49 students in the class

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the students that watched TV on Monday

-The set B represents the student that watched TV on Tuesday.

-The set C represents the students that watched TV on Wednesday.

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a is the number of students that only watched TV on Monday, A \cap B is the number of adults that watched TV both on Monday and Tuesday, A \cap C is the number of students that watched TV both on Monday and Wednesday, and A \cap B \cap C is the number of students that watched TV on every day.

By the same logic, we have:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

This diagram has the following subsets:

a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)

The sums of all of this values is the number of student that were there in the class. This means that we want to find the value of T:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = T

We start finding the values from the intersection of three sets.

Solution:

12 students watched TV on all three days:

A \cap B \cap C = 12

14 students watched TV on both Monday and Tuesday

A \cap B + A \cap B \cap C = 14

A \cap B = 14 - 12

A \cap B = 2

Of those who watched TV on only one of these days, 13 choose Monday, 9 chose Tuesday, and 10 chose Wednesday.

a = 13, b = 9, c = 10

29 students watched television on Monday:

A = 29

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

29 = 13 + 2 + (A \cap C) + 12

A \cap C = 29 - 27

A \cap C = 2

24 on Tuesday

B = 24

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

24 = 9 + (B \cap C) + 2 + 12

B \cap C = 24 - 23

B \cap C = 1

Now we have every value needed to find T:

T = a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)

T = 13 + 9 + 10 + 2 + 2 + 1 + 12

T = 49

There were 49 students in the class

7 0
4 years ago
Learning Task No. 1 Randy, Manny and Jan put 3 As, 4 Bs and 5 Cs in the box. They will take turns in getting a letter from the b
wolverine [178]

Answer:

1. A = 3/12

B= 4/12

C = 5/12

2......

3. Randy

Step-by-step explanation:

3+4+5 = 12

therefore there are 12 letters in the box

we can say that there are 3/12 A's in the box and do the same for the remaining letters

question two does not make sense

3. the person who has the lowest fraction in value which is A

6 0
4 years ago
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