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Vinvika [58]
2 years ago
8

Evaluate the Expression when b=3

la1" title=" {b}^{2} - 6b - 5" alt=" {b}^{2} - 6b - 5" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
meriva2 years ago
5 0
Now let’s evaluate this down if b=3 then you do 3x3 because b is squared which equals 9 then we do 6b which is 18, so 9-18 is (-9) then we do -9 - 5 which is -14
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PLEASE ANSWER ASAP FOR BRANLEST!!!!!!!!!!!!!!!
adoni [48]

Answer:

t = 8

Step-by-step explanation:

8 0
3 years ago
Suppose small aircraft arrive at a certain airport according to a Poisson process with rate a 5 8 per hour, so that the number o
timurjin [86]

Answer:

(a) P (X = 6) = 0.12214, P (X ≥ 6) = 0.8088, P (X ≥ 10) = 0.2834.

(b) The expected value of the number of small aircraft that arrive during a 90-min period is 12 and standard deviation is 3.464.

(c) P (X ≥ 20) = 0.5298 and P (X ≤ 10) = 0.0108.

Step-by-step explanation:

Let the random variable <em>X</em> = number of aircraft arrive at a certain airport during 1-hour period.

The arrival rate is, <em>λ</em>t = 8 per hour.

(a)

For <em>t</em> = 1 the average number of aircraft arrival is:

\lambda t=8\times 1=8

The probability distribution of a Poisson distribution is:

P(X=x)=\frac{e^{-8}(8)^{x}}{x!}

Compute the value of P (X = 6) as follows:

P(X=6)=\frac{e^{-8}(8)^{6}}{6!}\\=\frac{0.00034\times262144}{720}\\ =0.12214

Thus, the probability that exactly 6 small aircraft arrive during a 1-hour period is 0.12214.

Compute the value of P (X ≥ 6) as follows:

P(X\geq 6)=1-P(X

Thus, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8088.

Compute the value of P (X ≥ 10) as follows:

P(X\geq 10)=1-P(X

Thus, the probability that at least 10 small aircraft arrive during a 1-hour period is 0.2834.

(b)

For <em>t</em> = 90 minutes = 1.5 hour, the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 1.5=12

The expected value of the number of small aircraft that arrive during a 90-min period is 12.

The standard deviation is:

SD=\sqrt{\lambda t}=\sqrt{12}=3.464

The standard deviation of the number of small aircraft that arrive during a 90-min period is 3.464.

(c)

For <em>t</em> = 2.5 the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 2.5=20

Compute the value of P (X ≥ 20) as follows:

P(X\geq 20)=1-P(X

Thus, the probability that at least 20 small aircraft arrive during a 2.5-hour period is 0.5298.

Compute the value of P (X ≤ 10) as follows:

P(X\leq 10)=\sum\limits^{10}_{x=0}(\frac{e^{-20}(20)^{x}}{x!})\\=0.01081\\\approx0.0108

Thus, the probability that at most 10 small aircraft arrive during a 2.5-hour period is 0.0108.

8 0
2 years ago
On a coordinate plane, what is the difference between (-2,7) and (-2,-6)?
Shtirlitz [24]
If you mean distance, then we can use the distance formula to find out.

(x - x)² + (y - y)² = d²   Distance formula
(-2 + 2)² + (7 + 6)² = d²   Substitute the points; remember that when you subtract a negative, you add, and also remember to always subtract in the same direction (with the points (1,2) and (3,4), if you do 1 - 3, then do 2 - 4 and not 4 - 2)
(0)² + (13)² = d²   Add
0 + 169 = d²   Square
169 = d²   Add
13 = d   Take the square root of both sides to cancel out the exponent

The distance between (-2,7) and (-2,-6) is 13 units.

Hope this helps!
4 0
2 years ago
What is the least common denominator of the equation 2/9 and 2/3
inna [77]
The least common denominator would be 9, because

a. you can't take 3 out of two in 2/9

b. you can multiply 2/3 by 3 to make 6/9

so the LCD is 9
4 0
3 years ago
ordyn went out to lunch. She likes to tip on the taxed amount. Her meal cost $25. There is a 8% tax and she will leave 20% of ta
igor_vitrenko [27]
2ok is the answer loliliodbjshdhdgrh to
5 0
2 years ago
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