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3 years ago

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Evaluate the Expression when b=3

la1" title=" {b}^{2} - 6b - 5" alt=" {b}^{2} - 6b - 5" align="absmiddle" class="latex-formula">

1 answer:

meriva3 years ago

5 0

Now let’s evaluate this down if b=3 then you do 3x3 because b is squared which equals 9 then we do 6b which is 18, so 9-18 is (-9) then we do -9 - 5 which is -14

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A cab charges $1.45 for a flat fee and $0.55 for each mile. write and solve an inequality to determine how many miles Ariel can

BigorU [14]

35-1.45=33.55
33.55/0.55=62
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3 years ago

Jacob is working two summer jobs, making $10 per hour washing cars and making $8 per hour landscaping. In a given week, he can w

Burka [1]

Answer:

Step-by-step explanation:

Let x represent the number of hours that that he spent washing cars.

Let y represent the number of hours that that he spent landscaping.

In a week, he can work no more than 19 total hours. This means that

x + y ≤ 19- - - - - - - - - - - -1

Jacob is working two summer jobs, making $10 per hour washing cars and making $8 per hour landscaping. He must earn at least $170. This means that

10x + 8y ≥ 170 - - - - - - - - - -2

If Jacob worked 4 hours landscaping, it means that

x + 4 ≤ 19

x ≤ 19 - 4

x ≤ 15

Also,

10x + 8 × 4 ≥ 170

10x + 32 ≥ 170

10x ≥ 170 - 32

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10x ≥ 138/10

x ≥ 13.8

The minimum number of hours is 14

6 0

3 years ago

Oranges sell for $5.00 per bag. If there are 10 oranges in each bag, how much is the price per orange?

yulyashka [42]

Answer:

The answer is A

Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref

hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

$\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}$

So the cost of laying pipe under water with this distance is

$800000\sqrt{(3 - d)^2 + 4}$

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

$800000\sqrt{(3 - d)^2 + 4} + 400000d$

We can find the minimum value of this by taking the 1st derivative and set it to 0

$800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0$

We can move the first term over to the right hand side and divide both sides by 400000

$1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}$

$\sqrt{(3 - d)^2 + 4} = 6 - 2d$

From here we can square up both sides

$(3 - d)^2 + 4 = (6 - 2d)^2$

$9 - 6d + d^2 + 4 = 36 - 24d + 4d^2$

$3d^2-18d+27 = 0$

$d^2 - 6d + 9 = 0$

$(d - 3)^2 = 0$

$d -3 = 0$

d = 3

So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

3 0

3 years ago

Felipe received a $40.00 gift card for a photo center. He used it to buy prints that cost 8 cents each. The remaining balance, B

Neko [114]

For better representation, I think the function is written as:

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This is much more comprehensive. The variable x represents the number of prints. So, if x=40 prints, we replace this to the x in the equation to find the balance B.

B = 40 - 0.08(40)
<em>B = $36.8</em>

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3 years ago