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kondaur [170]
1 year ago
7

If the perimeter of a rectangle is 42 cm and the area is 98 square cm, then what are the dimensions of the rectangle?

Mathematics
1 answer:
Natalka [10]1 year ago
7 0

we are given that the perimeter of the rectangle is 42cm

the formula for the perimeter of the rectangle is 2(l+b)

where l= length and b=breadth

so,

equating the above two equations we get

2(l+b)=42

(l+b)=42/2

l+b=21..........................(1)

we are given the area of the rectangle to be 98sq cm

the formula for the area of the rectangle is l*b.

so,

equating the above two equations we get

l*b=98

l=98/b

equating the above equation in equation 1 in we get,

98/b +b=21

(98+b²)/b=21

98+b²=21b

b²- 21b + 98 = 0

(b-7)(b-14)=0

thus we have

b-7=0

b=7

and

b-14=0

b=14

equating both the values of b in equation (1)

when b=7

l+b=21

l+7=21

l=21-7

l=14

and

when b=14

l+b=21

l+14=21

l=21-14

l=7

since breath, can't be longer than length, thus b=7 and l=14.

thus the rectangle has a length of 14 cm and a breath of 7cm

Define the length and breadth/width of a rectangle.

Since a rectangle is a two-dimensional form, it has two dimensions: length and width. The rectangle's length is its longer side, while its width is its shorter side.

to learn more about parameters and areas visit:

brainly.com/question/19819849

#SPJ9

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Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]                            X=\left[\begin{array}{c}x\\y\end{array}\right]

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A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6

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A^{-1} ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}

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⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c}  {6}\\  {11} \end{array}\right]}

∴ x= 6 and y = 11

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