Question

If the perimeter of a rectangle is 42 cm and the area is 98 square cm, then what are the dimensions of the rectangle?

Answer 1

we are given that the perimeter of the rectangle is 42cm

the formula for the perimeter of the rectangle is 2(l+b)

where l= length and b=breadth

so,

equating the above two equations we get

2(l+b)=42

(l+b)=42/2

l+b=21..........................(1)

we are given the area of the rectangle to be 98sq cm

the formula for the area of the rectangle is l*b.

so,

equating the above two equations we get

l*b=98

l=98/b

equating the above equation in equation 1 in we get,

98/b +b=21

(98+b²)/b=21

98+b²=21b

b²- 21b + 98 = 0

(b-7)(b-14)=0

thus we have

b-7=0

b=7

and

b-14=0

b=14

equating both the values of b in equation (1)

when b=7

l+b=21

l+7=21

l=21-7

l=14

and

when b=14

l+b=21

l+14=21

l=21-14

l=7

since breath, can't be longer than length, thus b=7 and l=14.

thus the rectangle has a length of 14 cm and a breath of 7cm

Define the length and breadth/width of a rectangle.

Since a rectangle is a two-dimensional form, it has two dimensions: length and width. The rectangle's length is its longer side, while its width is its shorter side.

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