Question

Through (2,0) slope = -5/3 write the slope intercept of the equation

Answer 1

For this case we have that the equation of a line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

In this case we have the following data:

$m = - \frac {5} {3}\\(x, y) :( 2,0)$

Then, the equation is of the form:

$y = - \frac {5} {3} x + b$

We find "b" replacing the point:

$0 = - \frac {5} {3} (2) + b\\0 = - \frac {10} {3}\\b = \frac {10} {3}$

Thus, the equation is:

$y = - \frac {5} {3} x + \frac {10} {3}$

Answer:

$y = - \frac {5} {3} x + \frac {10} {3}$

Answer 2

Answer:

$y=-\frac{5}{3}x+\frac{10}{3}$

Step-by-step explanation:

The equation of a line has the following form:

$y=mx+b$

Where m is the slope of the line and b is the intercept with the y axis.

In this case we know that:

$m=-\frac{5}{3}$

So the equation is:

$y=-\frac{5}{3}x+b$

To find b we substitute the point in the equation and solve for b

$0=-\frac{5}{3}(2)+b$

$b=\frac{10}{3}$

Then the equation of the line in the form of pending interception is:

$y=-\frac{5}{3}x+\frac{10}{3}$